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faltersainse [42]
3 years ago
7

-7.08 as a fraction in simplest form

Mathematics
2 answers:
Slav-nsk [51]3 years ago
4 0

Answer:

-7 2/25

Step-by-step explanation:

Rewrite the decimal number as a fraction with 1 in the denominator

7.08= 7.08/1

Multiply to remove 2 decimal places. Here, you multiply top and bottom by 10^2= 100

7.08/1 ×100/100 =708/100

Find the Greatest Common Factor (GCF) of 708 and 100, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 4

In conclusion,

−7.08=−7 2/25

Alexeev081 [22]3 years ago
4 0
Convert to a mixed number by placing the numbers to the right of the decimal over
100
100
. Reduce the fraction. Then, convert the mixed number to an improper fraction by multiplying the denominator by the whole number and adding the numerator to get the new numerator. Place this new numerator over the original denominator.
−
177
25
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Aleonysh [2.5K]

Answer:

The simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

Step-by-step explanation:

The given expression is

\sqrt[3]{135}

According to the property of radical expression.

\sqrt[n]{x}=(x)^{\frac{1}{n}}

Using this property we get

\sqrt[3]{135}=(135)^{\frac{1}{3}}

\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3)^{\frac{1}{3}}\times (5)^{\frac{1}{3}}      [\because (ab)^x=a^xb^x]

\sqrt[3]{135}=3\times \sqrt[3]{5}     [\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]

\sqrt[3]{135}=3\sqrt[3]{5}

Therefore the simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

7 0
3 years ago
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Find the present value of the annuity.
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Pv=4,725×((1−(1+0.10÷2)^(−2
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3 years ago
9 to the power 3 + 3 to the power 2 + 6 to the power 3 + 15 power 2 equals to how much
Llana [10]
Hey! So, here's a tip. When writing exponents, an easier way is to write a^b, rather than a to the b power. Besides that, here is your answer!


So-------

9^3=729

3^2=9

6^3=216

15^2=225



Now that we have that figured out, we can add them together, wish is simple. 729 + 9 + 216 + 225= 1,179.



Therefore, your final answer will be 1,174.




If you have any questions on this, I'm happy to help you. :)




3 0
3 years ago
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A city planner designs a park that is a quadrilateral with vertices at J(−1, 1), K(1, 3), L(5, −1), and M(−3, −1). There is an e
Vadim26 [7]

use the eqn below to find the mid-pts

x-mid-pt = (x₁+x₂)/2

y-mid-pt = (y₁+y₂)/2

J(−1, 1), K(1, 3), L(5, −1), and M(−3, −1)

So

midpoint JK = (-1+1/2, 1+3/2) = (0,2)

midpoint KL = (1+5/2, 3+⁻1/2) = (3,1)

midpoint LM = (5+⁻3/2, ⁻1+⁻1/2) = (1,-1)

midpoint MJ = (⁻3+⁻1/2, -1+1/2) = (-2,0)


use the eqn to find distance:


d = √(x₂ - x₁)² + (y₂ - y₁)²


Distance between JK and LM = √(0⁻1)² + (2 - ⁻1)² = √1 + 9 = √10

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Scale is 10

Actual distance = 10*(√10 + √26) = 82.6 = 83 units


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4 years ago
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