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3 years ago

Will mark brainliest. Include explanation.

Mathematics

1 answer:

mihalych1998 [28]3 years ago

5 0

Answer:

D. 4x + 32; E. 4(x + 8)

Step-by-step explanation:

The correct answer is none. This problem is incorrect. The perimeter of a polygon is the sum of the lengths of all the sides. A perimeter is a length, not an area. A perimeter is expressed in feet, not square feet.

Ignoring the "square feet" part, once again, the perimeter is the sum of the lengths of all sides. Since this is a square, all sides have the same length, and there are 4 sides.

perimeter = 4s

perimeter = 4(x + 8) = 4x + 32

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There is no enough evidence that the repair cost for type I ovens is greater than the repair cost for type II ovens.

Step-by-step explanation:

We have to perform a hypothesis test on the difference of two means.

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- Sample mean: 70.15

- Sample standard deviation: 20.62

- Sample size: 43

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- Sample mean: 65.36

- Sample standard deviation: 22.21

- Sample size: 57

Step 1. The claim is that the repair cost for type I ovens (μ1) is greater than the repair cost for type II ovens (μ2). The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2>0$

Step 2.

The difference between the sample means is:

$M_d=\bar x_1-\bar x_2=70.15-65.36=4.76$

The standard error of the difference between means is:

$s_{M_d}=\sqrt{\frac{s_1^2}{n_1}+ \frac{s_2^2}{n_2}}=\sqrt{\frac{20.62^2}{43}+ \frac{22.21^2}{57}}=\sqrt{ 9.89 +8.65}=\sqrt{18.54}\\\\s_{M_d}=4.3$

The degrees of freedom are:

$df=n_1+n_2-2=43+57-2=98$

The t-statistic is

$t=\frac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\frac{4.76-0}{4.3}=1.11$

Step 3. The critical value for a right tail test with significance level of 0.05 and 98 degrees of freedom is t=1.66.

Then, if the test statistic is higher than 1.66, the effect is significant and the null hypothesis is rejected (rejection region).

If not, the null hypothesis is not rejected (acceptance region).

Step 4. The t-statistic is below the critical value, so the null hypothesis is not rejected.

There is no enough evidence that the repair cost for type I ovens is greater than the repair cost for type II ovens.

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