Answer: 2(x+3)=10 x=2
5(x+4)=25 x=1
Step-by-step explanation:
Answer:
-4.20c-5.55
Step-by-step explanation:
add -8.55c and 4.35c to simplify
Velocity is given as 80 feet per second, so replace V with 80.
The rocket is launched from the ground so the initial height is 0, so replace h with 0
The formula now becomes" h(t) = -16t^2 + 80t +0
To find the maximum we need to find the coordinates of the vertex by finding the axis of symmetry:
-b/2a = -80/(2*-16) = -80/-32 = 2.5
This represents the amount of time for the rocket to reach maximum height.
So we now replace t in the equation with 2.5 and solve for the height:
h(2.5) = -16(2.5)^2 + 80(2.5)
h(2.5) = 100
The maximum height is 100 feet
That would be (k^2 y^2), or simply (ky)^2 .
