All categories

3 years ago

Can some please answer and explain this question? Thanks.

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

4 0

A^2 + B^2 = C^2 so either the biggest number provided is C or it’s not.

\/10^2 + \/6^2 = 16... C = sq.root of 16, 4

Or

You might be interested in

a fish is 12 meters below the surface of the ocean. A sea bird is 28 meters above the surface. how far apart are they?

kolbaska11 [484]

answer is 40

Step-by-step explanation:

4 0

3 years ago

The volume of Mikes rectangular lunch box is 240 cubic inches. The lunchbox is 3 inches deep and its length is 2 inches more the

allochka39001 [22]

Answer:

8 inches

Step-by-step explanation:

You first divide 240 by 3 which is 80

Then you find what number is 2 less than the other number that is you multiplied together you get 80

And we know that 8 × 10 = 80

There for the :-

Width is 8 in

Length is 10 in

Hight is 3 in

The proof is if you multiply all of them you have to get 240

And if you multiply 8, 10, and 3 you get 240

6 0

2 years ago

150°<br>(3x – 15) what is x

Olin [163]

Answer:

3(x-5)

Step-by-step explanation:

7 0

3 years ago

Which number is an integer?<br> -34 -0.4 0.4 3.4 PLS HELP I'M TIMED EDGE 2020

Stella [2.4K]

Answer:

Step-by-step explanation: The four numbers: - 34, -0.4, 0.4, 3.4

so if you look at it it The answer is -34

7 0

3 years ago

Read 2 more answers

Clark and Lana take a 30-year home mortgage of $128,000 at 7.8%, compounded monthly. They make their regular monthly payments fo

svp [43]

Answer:

Step-by-step explanation:

From the given information:

The present value of the house = 128000

interest rate compounded monthly r = 7.8% = 0.078

number of months in a year n= 12

duration of time t = 30 years

To find their regular monthly payment, we have:

$PV = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{r}{n})^{-nt}}{\dfrac{r}{n}} \end {bmatrix}$

$128000 = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{0.078}{12})^{- 12*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

128000 = 138.914 P

P = 128000/138.914

P = $921.433

∴ Their regular monthly payment P = $921.433

To find the unpaid balance when they begin paying the $1400.

when they begin the payment ,

t = 30 year - 5years

t= 25 years

$PV= 921.433 \begin {bmatrix} \dfrac{1 - (1 - \dfrac{0.078}{12})^{25*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

PV = $121718.2714

C) In order to estimate how many payments of $1400 it will take to pay off the loan, we have:

$121718.2714 = \begin {bmatrix} \dfrac{1300 (1 - \dfrac{12.078}{12}))^{-nt}}{\dfrac{0.078}{12}} \end {bmatrix}$

$121718.2714 = 200000 \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$\dfrac{121718.2714}{200000 } = \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$0.60859 = \begin {bmatrix} (1 - \dfrac{12}{12.078}))^{nt} \end {bmatrix}$

$0.60859 = (0.006458)^{nt}$

$nt = \dfrac{0.60859}{0.006458}$

nt = 94.238 payments is required to pay off the loan.

How much interest will they save by paying the loan using the number of payments from part (c)?

The total amount of interest payed on $921.433 = 921.433 × 30(12) years

= 331715.88

The total amount paid using 921.433 and 1300 = (921.433 × 60 )+( 1300 + 94.238)

= 177795.38

The amount of interest saved = 331715.88 - 177795.38

The amount of interest saved = $153920.5

6 0

4 years ago