Answer: The radius is 5. Hopefully this helps. :)
Step-by-step explanation:
V = π r2 h 125/5=25
125π = π r2 5 r2=25
125π= π*5^2*5 r=5
If the value of cos(θ) is negative, this angle (θ) can only be in one of two quadrants; the sine quadrant or the tan quadrant. In the sine quadrant, tan(θ) must be negative, but since tan(θ) > 0, we can safely say that the angle (<span>θ) is based in the tan quadrant.
We know that cos(</span><span>θ) = - Adjacent / Hypotenuse, and in this case Adjacent = 2 and Hypotenuse = 5. Using Pythagoras' theorem, we can find the opposite side of the right angled triangle situated in the tan quadrant...
</span>Adjacent² + Opposite² = Hypotenuse²
Therefore:
2² + Opposite² = 5²
Opposite² = 5² - 2²
Opposite² = 21
Opposite = √(21)
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Now, sin(θ) must be negative, as the right angled triangle is in the tan quadrant. We also know that sin(<span>θ) = Opposite / Hypotenuse, therefore:
sin(</span><span>θ) = - [</span>√(21)]/[5]
The answer for this question would be 156
<span>C. It has two real solutions.
The discriminant in solving a quadratic equation is b^2-4ac. If this is greater than zero it has two real solutions.</span>
The correct answer is A = 41+3b/x+27/x
B = ax/3-41x/3 - 9
