Multiply 2 and 10
divide y and 2
add 2 and 10 and subract ten from it
Answer:6.2 and 6.5
Step-by-step explanation:
First, make a plotline from least to greatest and organize your list of numbers from least to Greatest.
Next, go through your list of organized numbers and add a dot to that number on the plotline. Repeat until done with list of numbers.
Then, go through your plotline and find the number(s) with the most dots and you have your mode.
Definition of mode: The number which appears most often in a set of numbers.
Answer:
<em><u>I</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>you</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
-17 + n/5 = 33
First, we can start out by regrouping our terms. This will switch our fraction and number around and also make the original addition to subtraction.

Second, we can start out our goal by trying to get the variable (n) on one side by itself and to equal something. Let's begin by adding 17 to each side of the problem.

Third, we can now add the numbers on the right side of our problem. Simple. Add 33 + 17 to get 50.

Fourth, we now have to multiply both sides by 5. Why? We are getting rid of the fraction so that the variable can become by itself.

Fifth, our last step is to multiply 50 × 5. Use a calculator, long multiplication, etc. 50 × 5 = 250.

Answer:
Answer:
5
Step-by-step explanation:
We are being asked in how many ways an enumerated ball can be removed without any type of replacement, therefore it would be a combination without repetition:
nCr = n! / r! * (n-r)!
n, total number of balls, 5
r, specific number of balls, 1
5C1 = 5! / (1! * 4!) = 5
Therefore there are 5 ways to do the above.