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The time required for one wing beat is 5 milliseconds.
<em><u>Explanation</u></em>
Lets assume, the time required for one wing beat is seconds
So, the time required for 200 wing beat seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...
So, the time required for one wing beat is 5 milliseconds.
Answer:
<h2>Question 13 : x = 62°</h2><h2>Question 14 : x = 2</h2>Step-by-step explanation:
Question 13
The diagram in question 13 is a triangle.
The sum of interior angles of a triangle is equal to 180°
To solve for x ;
Question 14
(: represents ratio or /)
x/9 = 18/81
Cross Multiply
81x = 18×9
81x = 162
Divide both sides of the equation by 81
81x/81 = 162/81
x = 2