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Vadim26 [7]
3 years ago
15

Please help with this math question

Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0
The answer would be D because if you notice the ratios between coordinates and their placement, the first transformation divides the coordinates by 8, or dilating it by a scale factor of 1/8. Then, in the second transformation, each of the coordinates' x-values increased by four, so it moves over four spaces to the right.
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Find the variation constant and an equation of variation where y varies directly as x and y=24 when x=3.
Kay [80]

Answer:

8

Step-by-step explanation:

y=x, y=kx, k is a constant, k/x=y/x, k=y/x, k=24/3, k=8

8 0
3 years ago
F(x)=2x and g(x)=2x+3,what is the value of f(g(-8))
jok3333 [9.3K]

Answer:

f(g(-8)) = -26

Step-by-step explanation:

Given:

f(x)=2x and g(x)=2x+3

Required:

f(g(-8))=?

Solution:

First we will find g(-8)

g(x) = 2x+3

g(-8)= 2(-8)+3

      = -16 + 3

      = -13.

so, g(-8) = -13

Now, for calculation f(g(-8)) we can put the value of g(-8) i.e, -13

so, f(x) = 2x

    f(-13)  = 2(-13)

             = -26

so, f(-13) = -26

and f(g(-8)) = -26

4 0
3 years ago
8 ÷ 3/5 Equals? I need this quickly.
cricket20 [7]

Answer:

= 40/3    =  13  1/3  

Step-by-step explanation:

8/1 ÷ 3/5     =   8/1 x 5/3

                         8 x 5 = 40

                          1 x 3 = 3

= 40/3    =  13  1/3

6 0
3 years ago
What is 9x-5x ????i need help
Dima020 [189]

Hi there!

Answer:

<u><em>=4x</em></u>

Step-by-step explanation:

Distributive property: ⇒ a(b+c)=ab+ac

You had to add similar elements.

9x-5x=4x

5x+4x=9x

9x-4x=5x

final answer: =4x

Hope this helps!

-Charlie

Have a great day!

4 0
3 years ago
The speed of sound in water is 1498 m/s. a sonar signal is sent straight down from a ship at a point just below the water surfac
bulgar [2K]
The 1.8 s is the time for the signal to reach the ocean floor and return to the ship so the time to reach ocean floor = 1.8 / 2 = 0.90 seconds.
depth of ocean = speed * time

=  1498 * 0.90  =  1348.2 m  Answer
8 0
3 years ago
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