Line L passes through the points (1, 5) and (5, 8). What is the slope of a line that is perpendicular to line L?
1 answer:
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Answer:
Step-by-step explanation:
Let
y=2x-10
Switch x and y,
x=2y-10
x+10=2y
(x/2)+5=y
So
Answer:
Equation of the straight line passing through the point ( 1,2 ) and having the slope
x - √3y -1+2√3 =0
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the point (1,2) and an angle = ∝ = 30°
The slope of the line
m = tan 30°
<u><em>Step(ii)</em></u>:-
Equation of the straight line passing through the point ( 1,2 ) and having the slope
y - y₁ = m(x-x₁)
y - 2 = ( x -1)
√3(y-2) = (x-1)
⇒ √3y - 2√3 = x -1
x - √3y -1+2√3 =0