A recursive sequence is a sequence of numbers whose values are determined by the numbers that come before them in the sequence.
We’re given a sequence whose (n + 1)-th term f(n + 1) depends on the value of the n-th term f(n), specified by the recursive rule
f(n + 1) = -4 f(n) + 3
We’re also given the 1st term in the sequence, f(1) = 1. Using this value and the recursive rule, we can find the next term f(2). (Just replace n with 1.)
f(1 + 1) = -4 f(1) + 3
f(2) = -4 • 1 + 3
f(2) = -1
We do the same thing to find the next term f(3) :
f(2 + 1) = -4 f(2) + 3
f(3) = -4 • (-1) + 3
f(3) = 7
One more time to find the next term f(4) :
f(3 + 1) = -4 f(3) + 3
f(4) = -4 • 7 + 3
f(4) = -25
B^2-6b+8 turns into b^2-2b-4b+8 due to the sum product pattern. which then turns into b(b-2) - 4(b-2) and then its (b-4)(b-2)
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Answer:
y=x-6
Step-by-step explanation:
The x-intercept is found replacing y = 0, as follows:
<u>Function:</u> y = -3x + 8
x-intercept:
0 = -3x + 8
3x = 8
x = 8/3
<u>Function</u>: y = -3x + 6
x-intercept:
0 = -3x + 6
3x = 6
x = 6/3 = 2
<u>Function</u>: y = -x - 8
x-intercept:
0 = -x - 8
x = -8
<u>Function</u>: y = x - 6
x-intercept:
0 = x - 6
x = 6
The last option is the only one in which x-intercept is x = 6.
Answer:
√208
Step-by-step explanation:
Step 1: Convert 4 to √
4² = 16
4 = √16
Step 2: Multiply radicals
√16(√13) = √208