Question

PLEASE help. Will give brainliest.

Answer 1

Answer:

y=5

x=10 and

z=2

Step-by-step explanation:

since they are equivalance then,

for

triangle ABC and triangle DFE

AB=DF,BC=FE and AC= DE

So, AB=DF

8y-20= 4y

or, y=5

Then, BC= FE

2x+5=x+15

or, x=10

and

AC=DE

3z+9=10z-5

or, z= 2

hope u got ut.

Answer 2

The triangles are parallel thus their sides are equal to each other peer to peer.

So ;

$x + 15 = 2x + 5$

Subtract sides -5

$x + 15 - 5 = 2x + 5 - 5$

$x + 10 = 2x$

Subtract sides -x

$x - x + 10 = 2x - x$

$x = 10$

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$4y = 8y - 20$

Subtract sides -8y

$4y - 8y = 8y - 8y - 20$

$- 4y = - 20$

Negatives simplifies

$4y = 20$

Divided sides by 4

$\frac{4}{4}y = \frac{20}{4}$

$y = 5$

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$10z - 5 = 3z + 9$

Plus sides 5

$10z - 5 + 5 = 3z + 9 + 5$

$10z = 3z + 14$

Subtract sides -3z

$10z - 3z = 3z - 3z + 14$

$7z = 14$

Divided sides by 7

$\frac{7}{7}z = \frac{14}{7}$

$z = 2$

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And we're done....♥️♥️♥️♥️♥️