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3 years ago

I need help asap please

Mathematics

2 answers:

Gnesinka [82]3 years ago

6 0

The answer is B!
good luck with the rest of your hw!

kherson [118]3 years ago

3 0

Answer:

D. 3x^4 - 10x^2 + 6

Step-by-step explanation:

Let's work our way from the front of the equation to the back.

x^2 x 3x^2

to make this easier we are gonna separate the exponent and deal with that after.

x x 3x

Well that is basically 1 x 3 so that is 3. So we can easily cross out A.

Now we can deal with the exponents. When the equations are multiplying, we are gonna add the exponents.

2 + 2 = 4.

Okay, now let's deal with -5x and 2x

-5x x 2x

Easy, just multiply the numbers while adding the exponents like we did before.

-10x^2

And if you look at the 3 remaining answers

Only D. starts off with 3x^4 -10x^2

So eliminating the rest, now you are left it D as the answer

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This is 15 points plz help ( no links ) EXPLAIN YOUR ANSWER plz

goldfiish [28.3K]

A.
EXPLANATION:
The mode is the peak of the data, in this data set, 5/8
The median is the center of data, in the data set, 1/2
5/8>1/2
Mode>Median

6 0

3 years ago

A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar

ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let $\mu$ = mean waiting time for bus number 14.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 10 minutes {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, $H_A$ : $\mu$ < 10 minutes {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean waiting time = 7.8 minutes

s = sample standard deviation = 2.5 minutes

n = sample of different occasions = 18

So, test statistics = $\frac{7.8-10}{\frac{2.5}{\sqrt{18} } }$ ~ $t_1_7$

= -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0

3 years ago

Hop on the baby waveeeee. put your baby pic as your profile pic to make a trenddddd

Alex787 [66]

Answer:

I did it is in my profile

Step-by-step explanation:

8 0

3 years ago

The Quinn family drove 228 miles in 4 hours at a constant rate. Which equation can be used to determine how far they traveled ea

anyanavicka [17]

What can be used on this is the distance over time formula, so what you,do is divide 228 by 4 to get the distance traveled in one hour. And 288/4=57. So they traveled 57 mi in one hour. Hope this helped.

6 0

2 years ago

Read 2 more answers

The rule for this number sequence is (n+3) x 2

zzz [600]

6 + 12 = 18
18 + 24 = 42
Double the difference between every 2 numbers (12 x 2 = 24 x 2 = 8)
42 + 48 = 90
90 is the missing number
Happy to Help!

8 0

3 years ago