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3 years ago

I need help asap please

Mathematics

2 answers:

Gnesinka [82]3 years ago

6 0

The answer is B!
good luck with the rest of your hw!

kherson [118]3 years ago

3 0

Answer:

D. 3x^4 - 10x^2 + 6

Step-by-step explanation:

Let's work our way from the front of the equation to the back.

x^2 x 3x^2

to make this easier we are gonna separate the exponent and deal with that after.

x x 3x

Well that is basically 1 x 3 so that is 3. So we can easily cross out A.

Now we can deal with the exponents. When the equations are multiplying, we are gonna add the exponents.

2 + 2 = 4.

Okay, now let's deal with -5x and 2x

-5x x 2x

Easy, just multiply the numbers while adding the exponents like we did before.

-10x^2

And if you look at the 3 remaining answers

Only D. starts off with 3x^4 -10x^2

So eliminating the rest, now you are left it D as the answer

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What are the coordinates of each point after quadrilateral ABCD is reflected across the y-axis and then translated 2 units down?

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$A" =(-1,-1)$ $B" =(-2,1)$

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$A = (1,1)$ $B =(2,3)$

$C = (4,3)$ $D = (5,1)$

Required

The new coordinates after reflected across y-axis and shifted 2 units down

When a point is reflected across the y-axis, the rule is:

$(x,y)=>(-x,y)$

So:

$A = (1,1)$ $=> A' = (-1,1)$

$B =(2,3)$ $=> B' = (-2,3)$

$C = (4,3)$ $=> C' = (-4,3)$

$D = (5,1)$ $=> D' = (-5,1)$

When a point is translated 2 units down, the rule is:

$(x,y) => (x,y-2)$

So:

$A = (1,1)$ $=> A' = (-1,1)$ $=> A" =(-1,-1)$

$B =(2,3)$ $=> B' = (-2,3)$ $=> B" =(-2,1)$

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$D = (5,1)$ $=> D' = (-5,1)$ $=> D" =(-5,-1)$

So, the new coordinates are:

$A" =(-1,-1)$ $B" =(-2,1)$

$C" =(-4,1)$ $D" =(-5,-1)$

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