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alexira [117]
3 years ago
13

A recipe requires 1/3 cup of milk for each 1/4 cup of water. How many cups of water are needed for each cup of milk?

Mathematics
2 answers:
DaniilM [7]3 years ago
8 0
Three/fourths  cups of water for each cup of milk
raketka [301]3 years ago
7 0
The answer would be B because you have to multiply 1/3 by 3 to get a whole cup.  Therefore, you have to multiply 1/4 by 3 also.  In this case, the answer would be 3/4.  Hope this helps!
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I got 7/8 the answer
6 0
3 years ago
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The price of a 7-minute phone call is $1.05. What is the price of a 19-minute phone call
Leni [432]

Answer:

19.95

Step-by-step explanation:

if you take 1.05 times it by 19 you get your answer

7 0
3 years ago
I need help with this problemmm, someone help mee!!.
Varvara68 [4.7K]

Answer:

∠A=30°

Step-by-step explanation:

let's call the angle at the bottom B and the one next to the 130 C

∠A=3x-6

∠C=180-130= 50°

vertical angles are equal∠B =8x+4

∠A+∠C+∠B=180°

find x:

3x-6+50+8x+4= 180°

11x+48=180°

11x= 132

x=12

find ∠A

∠A=3x-6= 3(12)-6 =30°

5 0
3 years ago
1. A boat is 15 ft away from a point perpendicular to the shoreline. A person stands at a point down the shoreline so that a 65°
ratelena [41]
1.) Let the distance of the person from the boat be x, then
sin 65 = 15/h
h = 15 / sin 65 = 16.55 ft

2.) No triangle shown

3.) Let the angle of elevation of the sun be x, then
tan x = 35 / 50 = 0.7
x = arctan (0.7) = 34.99
7 0
3 years ago
La suma dels quadrats de tres nombres naturals consecutius i múltiples de 3 és igual a 450. Planteja una equació de segon grau i
Firlakuza [10]

Answer:

The 3 numbers are 9, 12, and 15.

Step-by-step explanation:

I will answer in English, below the answer you can see a translation in Catalan.

This can be translated to:

The sum of the squares of three consecutive and multiple natural numbers of 3 is equal to 450. Pose a quadratic equation and calculate the three numbers.

First, a multiple of 3 can be written as:

3*n

The consecutive multiple of 3 is:

3*n + 3

The consecutive multiple of 3 is:

3*n + 3 + 3

Then the sum of their squares is:

(3*n)^2 + (3*n + 3)^2 + (3*n + 6)^2

And we know that this is equal to 450, then we need to solve the equation:

(3*n)^2 + (3*n + 3)^2 + (3*n + 6)^2 = 450

let's solve this:

9*n^2 + (9*n^2 + 2*(3*n)*3 + 9) + (9*n^2 + 2*(3*n)*6 + 36) = 450

27*n^2 + 54*n + 45 = 450

we can write this as:

27*n^2 + 54*n + 45 - 450 = 0

27*n^2 + 54*n - 405 = 0

The solutions of this equation are given by the Bhaskara's formula, and the solutions are:

n = \frac{-54 \pm \sqrt{54^2 -4*27*(-415)}  }{2*27} = \frac{-54 \pm 216 }{54}

we know that our numbers are naturals, then the numbers are positives, which means that we only care for the positive solution of n, which is:

n = (-54 + 216)/54 = 3

Then the 3 numbers are:

3*n = 3*3 = 9

(3*n + 3) = (3*3 + 3) = 12

(3*n + 6) = (3*3 + 6) = 15

In Catalan:

En primer lloc, es pot escriure un múltiple de 3 com:

3 * n

El múltiple consecutiu de 3 és:

3 * n + 3

El múltiple consecutiu de 3 és:

3 * n + 3 + 3

Llavors, la suma dels seus quadrats és:

(3 * n) ^ 2 + (3 * n + 3) ^ 2 + (3 * n + 6) ^ 2

I sabem que això és igual a 450, llavors hem de resoldre l’equació:

(3 * n) ^ 2 + (3 * n + 3) ^ 2 + (3 * n + 6) ^ 2 = 450

resolem això:

9 * n ^ 2 + (9 * n ^ 2 + 2 * (3 * n) * 3 + 9) + (9 * n ^ 2 + 2 * (3 * n) * 6 + 36) = 450

27 * n ^ 2 + 54 * n + 45 = 450

podem escriure això com:

27 * n ^ 2 + 54 * n + 45 - 450 = 0

27 * n ^ 2 + 54 * n - 405 = 0

Les solucions d’aquesta equació vénen donades per la fórmula de Bhaskara, i les solucions són:

n = \frac{-54 \pm \sqrt{54^2 -4*27*(-415)}  }{2*27} = \frac{-54 \pm 216 }{54}

sabem que els nostres nombres són naturals, aleshores els nombres són positius, cosa que significa que només ens importa la solució positiva de n, que és:

n = (-54 + 216) / 54 = 3

Llavors els 3 nombres són:

3 * n = 3 * 3 = 9

(3 * n + 3) = (3 * 3 + 3) = 12

(3 * n + 6) = (3 * 3 + 6) = 15

7 0
3 years ago
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