Answer:
✔️The measure of angle <CBA is equal to the measure of angle <DBE.
✔️The measure of angle CBD is equal to the measure of angle ABE.
✔️The sum of the measures of angles CBD and CBA is 180 degrees.
Step-by-step explanation:
Vertical angles are formed when two straight lines intersect each other at a certain point. The diagram given is a typical example. This, vertical opposite angles formed are said to be congruent, that is their measures are equal to each other.
The following statements are true of the given diagram:
✔️The measure of angle <CBA is equal to the measure of angle <DBE.
(<CBA and ,<DBE are vertically opposite angles)
✔️The measure of angle CBD is equal to the measure of angle ABE.
(They are both vertically opposite angles)
✔️The sum of the measures of angles CBD and CBA is 180 degrees.
(<CBA and <CBD are supplementary angles)
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<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>
Step-by-step explanation:
let the 2 numbers be x and x + 4 as their deference is 4.
their sum = 50
now,
→ x + x + 4 = 50
→ 2x + 4 = 50
→ 2x = 50 - 4 = 46
→ x = 46/2 = 23
therefore two numbers are,
x = 23
x + 4 = 23 + 4 = 27
hope this answer helps you dear...take care and may u have a great day ahead!
the solid is made up of 2 regular octagons, 8 sides, joined up by 8 rectangles, one on each side towards the other octagonal face.
from the figure, we can see that the apothem is 5 for the octagons, and since each side is 3 cm long, the perimeter of one octagon is 3*8 = 24.
the standing up sides are simply rectangles of 8x3.
if we can just get the area of all those ten figures, and sum them up, that'd be the area of the solid.
![\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=5\\ p=24 \end{cases}\implies A=\cfrac{1}{2}(5)(24)\implies \stackrel{\textit{just for one octagon}}{A=60} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{two octagon's area}}{2(60)}~~+~~\stackrel{\textit{eight rectangle's area}}{8(3\cdot 8)}\implies 120+192\implies 312](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20regular%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dap~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20p%3Dperimeter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D5%5C%5C%20p%3D24%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%285%29%2824%29%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bjust%20for%20one%20octagon%7D%7D%7BA%3D60%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwo%20octagon%27s%20area%7D%7D%7B2%2860%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Beight%20rectangle%27s%20area%7D%7D%7B8%283%5Ccdot%208%29%7D%5Cimplies%20120%2B192%5Cimplies%20312)
Step-by-step explanation:
a=3/4
