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2 years ago

How do you solve this !!??(x+y+2)(y+1)

Mathematics

1 answer:

Elena-2011 [213]2 years ago

6 0

Answer:

Step-by-step explanation:

(x+y+2)(y+1)

Opening the brackets

xy + x + y^2 + y +2y +2

y^2 +xy + 3y + x +2

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Probability of a standard six side dice landing on a four in the first three rolls?

Illusion [34]

Answer:

91/216

Step-by-step explanation:

The probability of getting a 4 in the first three rolls is 1 minus the probability of not getting a 4 on any of the rolls.

P(at least one 4) = 1 − P(no 4s)

P(at least one 4) = 1 − (5/6)³

P(at least one 4) = 91/216

Alternatively, you can calculate it this way.

The probability of getting a 4 on the first roll is 1/6.

The probability of getting a 4 on the second roll is (5/6) (1/6) = 5/36.

The probability of getting a 4 on the third roll is (5/6) (5/6) (1/6) = 25/216.

The probability of any of the three events is 1/6 + 5/36 + 25/216 = 91/216.

6 0

2 years ago

Please help me please help me

Anon25 [30]

Answer:

AM=26

Step-by-step explanation:

Since M is the midpoint of the number line, this means that each side is equal to each other. The midpoint evenly splits it up in half, and since each side is equal that means we can set up an equation making x+20 and 5x-4 the same value.

x+20 = 5x-4

Now you simply carry over, so that x is all by itself. I carried the -4 to the other side first. To carry it over you have to add 4 on both sides, leaving this:

x+24=5x

Then I carried the x to the other side by subtracting -x (or if it helps, imagine an invisible one next to the x so it would be -1x) on both sides.

This gives me: 24=4x

Now that all the x's are by themelves, we can divide 24 by 4 to get our x value:

6=x

Now all we need to do is plug that in for the length of AM:

6+20, which equals our final answer 26

I hope you found this helpful :)

5 0

1 year ago

If you have a GCF of x is that a root?

Mekhanik [1.2K]

Answer:

No,

Step-by-step explanation:

No, GCF is not a root, it is the coefficient of x.

3 0

2 years ago

Check answer please

Cerrena [4.2K]

The fourth or the D) Option is correct.

To find the new induced matrix via a scalar quantified multiplication we have to multiply the scalar quantity with each element surrounded and provided in a composed (In this case) 3×3 or three times three matrix comprising 3 columns and 3 rows for each element which is having a valued numerical in each and every position.

Multiply the scalar quantity with each element with respect to its row and column positioning that is,

Row × Column. So;

(1 × 1) × 7, (2 × 1) × 7, (3 × 1) × 7, (1 × 2) × 7, (2 × 2) × 7, (3 × 2) × 7, (1 × 3) × 7, (2 × 3) × 7 and (3 × 3) × 7. This will provide the final answer, that is, the D) Option.

To interpret and make it more interesting in LaTeX form. Here is the solution with LaTeX induced matrix.

$\mathcal{A = \begin{bmatrix}1 & 0 & 3 \\ 2 & -1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}$

$\mathbf{\therefore \quad 7A = 7 \times \begin{bmatrix}1 & 0 & 3 \\ 2 & - 1 & 2 \\ 0 & 2 & 1 \\ \end{bmatrix}}$

$\mathbf{\therefore \quad \begin{bmatrix}7 \times 1 & 7 \times 0 & 7 \times 3 \\ 7 \times 2 & 7 \times -1 & 7 \times 2 \\ 7 \times 0 & 7 \times 2 & 7 \times 1 \\ \end{bmatrix}}$

$\therefore \quad \begin{\bmatrix}7 & 14 & 0 \\ 0 & -7 & 14 \\ 21 & 14 & 7 \end{bmatrix}$

Hope it helps.

5 0

2 years ago

Carter plans to read 4 books during summer break: Charlottes web, Grasshopper summer, Diary of a Wimpy Kid, and Diary of a Wimpy

Dmitrij [34]

Answer: 32

Step-by-step explanation:

4 x 4 x 4

7 0

2 years ago

Read 2 more answers