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klio [65]
3 years ago
6

Danielle has $6.65 worth of change in nickels and dimes. If she has 5 times as many nickels as dimes, how many of each type of c

oin does she have?
Mathematics
2 answers:
Wittaler [7]3 years ago
6 0

Answer:

There are 19 dimes and 95 nickels

Step-by-step explanation:

Represent the numbers of nickels and dimes by n and d.  Then n = 5d.

The value of the nickels is $0.05n and that of the dimes is $0.10d.  Together these two amounts come to $6.65:

$0.05n + $0.10d = $6.65.

But n = 5d.

Substituting 5d for n, we get:

$0.05(5d) + $0.10d = $6.65

Combining the two terms on the left, we get:

0.25d + 0.10d = 6.65, or

0.35d = 6.65.

Solving for d, we get d = 6.65/0.35, or d = 19.  Since n = 5d, n = 5(19) = 95.

There are 19 dimes and 95 nickels.

evablogger [386]3 years ago
4 0

Answer:

95 nickels 19 dimes

Step-by-step explanation:

d=dimes

5d=nickels

0.05(5d) + 0.10(d) = 6.65

0.25d + 0.10d = 6.65

0.35d=6.65

Divide by 0.35

d= 19 (19 coins)

19 dimes =$1.9

6.65-1.9= $4.75

Nickels=$4.75

4.75/0.05 = 95 coins

19*5=95

  114 coins in total

19*0.10 = 1.9

95*0.05=4.74

4.75+1.9= 6.65

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Answer:

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Step-by-step explanation:

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170% of 500 is 850

I hope this helps!

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What is 3/2=9/10k im having troble lots rly
tigry1 [53]

Answer:

k=  5 over 3  =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (3)/(2)-((9)/(10)*k)=0

simplify 9/10

 3      9

 — -  (—— • k)  = 0  

 2     10

simplify 3/2

 3    9k

 — -  ——  = 0  

 2    10

   Find the Least Common Multiple

     The left denominator is :       2  

     The right denominator is :       10

Least Common Multiple:

     10

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • 5

  ——————————————————  =   —————

        L.C.M              10  

  R. Mult. • R. Num.      9k

  ——————————————————  =   ——

        L.C.M             10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k)     15 - 9k

————————————  =  ———————

     10            10  

Pull out like factors :

  15 - 9k  =   -3 • (3k - 5)

-3 • (3k - 5)

 —————————————  = 0  

      10      

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -3•(3k-5)

 ————————— • 10 = 0 • 10

    10    

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -3  •  (3k-5)  = 0

Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    3k-5 = 0  

Add  5  to both sides of the equation :  

                     3k = 5

Divide both sides of the equation by 3:

                    k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

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