The constant is 3 because it has no variable.
The coefficient is 7b because it has a variable.
Let the three numbers be x, y and z respectively, then
x + y + z = 62 . . . (1)
y = x - 4 . . . (2)
z = 4x . . . (3)
The above three expressions could be used to represent the numbers.
Solving the three equations, putting (2) and (3) into (1) gives
x + x - 4 + 4x = 62
6x - 4 = 62
6x = 62 + 4 = 66
x = 66/6 = 11
x = 11.
y = 11 - 4 = 7
z = 4(11) = 44
x = 11, y = 7, z = 44.
Answer:
6y² - 20y + 6
Step-by-step explanation:
Use FOIL method
(3y - 1)(y-3) = 3y*y + 3y*(-3) + (-1)*y + (-1)*(-3)
= 3y²- 9y - y + 3 {add the like terms}
= 3y² - 10y + 3
2(3y - 1)(y - 3) = 2 ( 3y² - 10y + 3)
= 2*3y² - 2*10y + 2*3
= 6y² - 20y + 6
Given:
The three equations for the three numbers are
To find:
The Pythagorean triple generated by using 4 for x and 1 for y.
Solution:
Substituting x=4 and and y=1 in the given equations, we get
In the same way find b and c.
The third number is
The required Pythagorean triple is 8, 15, and 17.
Therefore, the correct option is C.
