Answer:
15 ft
Step-by-step explanation:
Pythagoras formula for a triangle with a 90 degree angle :
a^2 + b^2 = c^2
c is the side opposite of the 90 degree angle. exactly or situation here.
=> 9^2 + 12^2 = x^2
=> 81 + 144 = x^2 = 225
=> x = sqrt(225) = 15
1. Use a straightedge to draw line m and label a point on the line as point F
2. Construct a line perpendicular to line m through point F. Label a point on this line as point G.
3. With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.
4. Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK.
5. Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.
6. Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.
Answer:
The length of the segment AB is √48
Step-by-step explanation:
Given the two equations, the idea is to find the solution to the system
y = x² + 9
y = 2x² - 3
you can use the equality method to find the "x" and "y" of the solution.
x² + 9 = 2x² - 3 ⇒ x² - 2x² = -3 - 9 ⇒ -x² = -12 ⇒ x² = 12 ⇒ x = ±√12.
With this value we return to the original equations and replace it to find "y" values.
y = (±√12)² + 9 ⇒ y = 21
The solutions to the system are (-√12, 21) and (√12, 21). Now you need to find the distance between this points.
d= √[(x2-x1)² + (y2-y1)²] ⇒ d = √48.
The length of the segment AB is √48.
Answer:
123
Step-by-step explanation:
if the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadth
Answer:
total number of brown sugar cubes = 3
total number of white sugar cubes = 1
total number of sugar cubes = total no of brown sugar cubes + total no of white sugar cubes = 3 + 1 = 4
probability to select one brown sugar cube = total number of brown sugar cube / total number of sugar cube = 3/ 4
therefore the probability of selecting a brown sugar cube is 3/4 or 0.75
