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Sauron [17]
3 years ago
7

A child on a swing is pushed just once. The child moves a distance of 10

Mathematics
1 answer:
ziro4ka [17]3 years ago
5 0

the distance the child travels n  swings after the first is  Distance = 10(0.83)^n . Options A) and D) are identical , so kindly match Distance = 10(0.83)^n  with your answer !

<u>Step-by-step explanation:</u>

Here we have , A child on a swing is pushed just once. The child moves a distance of 10  feet the first swing, and then only 83%  as much as the previous swing for each one after. We need to find Which of the following sequences expresses the distance the child travels n  swings after the first . Let's find out:

Initially the distance is 10 feet from after the first swing . It's given that there is 83% as much as previous distance !

For first swing :

⇒ Distance = S_0 =10(0.83)

For second swing :

⇒ Distance = S_1 =10(0.83)^2

For third swing :

⇒ Distance = S_2 =(10(0.83^2))(0.83) = (S_1)0.83

⇒ Distance = S_2 =10(0.83)^2

So , For n swings :

⇒ Distance = 10(0.83)^n

Therefore , the distance the child travels n  swings after the first is  Distance = 10(0.83)^n .

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You bike 1 mile the first day of your​ training, 1.3 miles the second​ day, 1.9 miles the third​ day, and 3.1 miles the fourth d
JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

d_1=1 mi is the distance travelled during the 1st day

d_2=1.3 mi is the distance travelled during the 2nd day

d_3=1.9 mi is the distance travelled during the 3rd day

d_4=3.1 mi is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2

Which can be rewritten using the general formula:

d_{n+1}-d_n=2(d_n-d_{n-1})

This means that

d_{n+1}=d_n+2(d_n-d_{n-1})

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi

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7 0
3 years ago
Omar drew a number line that went from -10 to 10 and used it to compare integers. Which statement is true?
Evgen [1.6K]

Answer:

-7 < -3 because -7 is located to the left of -3 on a number line.

Step-by-step explanation:

This is because -7 is on the left of the -3. In negatives -3 is greater than -7. If it was positive then 7 would be greater than 3. So the answer is A. -7 < -3 because -7 is located to the left of -3 on a number line

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3 years ago
What is 3k-14=3(k-5)+1 ?
stealth61 [152]

Answer:

True

Step-by-step explanation:

3k-14=3(k-5)+1

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3k-3k=14-15+1

0=14-15+1

-14=-15+1

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8 0
3 years ago
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