Answer:
C 210
Step-by-step explanation:
To solve this, First we must take 42/3, Since it equals 14, we take 15x14 and find 210
(edit: to solve for Kim's missing values, you do the same with 2 and 32)
B^5 when you’re dividing exponents, just subtract!
Answer:
free throws = 6
2 points shots = 3
Step-by-step explanation:
To do this we will have 2 incognitas.
x = number of free throws
y = number of shots of 2 points
x(1) + y(2) = 12
he says he made twice as many free throws as 2 points
x = 2y
2y(1) + y(2) = 12
2y + 2y = 12
4y = 12
y = 12/4
y = 3
x = 2y
x = 2*3
x = 6
free throws = 6
2 points shots = 3
(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
