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2 years ago

The value of a baseball card can be represented by the equation Y - 3x439, where x represents the number of years

Mathematics

2 answers:

kobusy [5.1K]2 years ago

6 0

Answer:

1047 cards

Step-by-step explanation:

3x349=1047 3x300=900 3x40=120 3x9=27 900+120+27=1047

miv72 [106K]2 years ago

5 0

Answer: The actual answer is 39$

Step-by-step explanation:

y = 3(0) + 39

y = 0 + 39

y = $39

Therefore, Robert originally purchased the card for $39. I hoped this helped <3 no hate to the other person though

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15,000 blue trout were released into the Meherrin River for a scientific study. The function, f(x) = 15,000 (9/8)^x represents t

Ainat [17]

I'm guessing you mean f(x)=15,000(9/8)^x. If this is what you mean, the population would increase by about 12,000 (12030.4870605 to be exact).
Step-by-step explanation:
Starting equation: f(x)=15,000(9/8)^x
You can clean up the 9/8 to be 1.125
Now what you want to do is find the answer to (9/8)^5 which is 1.8020324707
Next multiply 1.8020324707 by 15,000 and you get 27030.4870605
Finally 27,030.4870605 - 15,000 gives you 12030.4870605. Which means that the population increased by about 12,000.

Please mark me brainiest cuz I need one more to level up!! Thank you

5 0

2 years ago

A certain car model has a mean gas mileage of 34 miles per gallon (mpg) with a standard deviation A pizza delivery company buys

zubka84 [21]

Answer:

$z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028$

$z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441$

An we can use the normal standard table and the following difference and we got this result:

$P(-1.028$

Step-by-step explanation:

Assuming this statement to complete the problem "with a standard deviation 5 mpg"

We have the following info given:

$\mu = 34$ represent the mean

$\sigma= 5$ represent the deviation

We have a sample size of n = 54 and we want to find this probability:

$P(33.3 < \bar X< 34.3)$

And for this case since the sample size is large enough >30 we can apply the central limit theorem and then we can use this distribution:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

And we can use the z score formula given by:

$z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028$

$z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441$

An we can use the normal standard table and the following difference and we got this result:

$P(-1.028$

7 0

3 years ago

In 2011, the Institute of Medicine (IOM), a non-profit group affiliated with the Select one US National Academy of Sciences, rev

Sergio [31]

Answer:

B. Yes, there are at least 10 people with weak bones and 10 people with strong bones in each group.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$