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harina [27]
3 years ago
5

What was the first 1.0.1 version of openssl that was not vulnerable to heartbleed?

Computers and Technology
2 answers:
vovikov84 [41]3 years ago
5 0
I suggest you to read OpenSSL changelogs to make it more clear. As there's not enough space to describe how it works. But heartbleed resistan version was 1.0.2, as I know.
user100 [1]3 years ago
3 0

Answer:

I suggest you to read OpenSSL changelogs to make it more clear. As there's not enough space to describe how it works. But heartbleed resistan version was 1.0.2, as I know.

Explanation:

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PLZ HELP!!!
mariarad [96]
Answer: A. Usability testing
Explanation:
Usability testing would be the correct answer because if the user interface isn't "frendly" then people won't be able to use it properly. Or if you are refering to the word friendly as looking safe, then even more so would be usability testing. Because if people don't like the fonts and styles of the user interface, they might not use it at all.
8 0
3 years ago
Consider the code fragment below (with nested loops). int sum = 0;for (int i = 1; i < 5; i++) for (int j = 1; j <= i; j++)
sammy [17]

Answer:

Option d is the correct answer for the above question.

Explanation:

  • The first loop of the program has a second loop and then the statement. In this scenario, the second loop executes for the value of the first loop and the statement executes for the value of the second loop.
  • The first loop executes 4 times, Then the second loop or inner loop executes n times for the n iteration of the first loop, for example, 1 time for the first iteration of the first loop, 2 times for the second iteration of the first loop and so on.
  • Then the inner loop executes (1+2+3+4) iteration which gives the result 10 iterations.
  • The sum initial value is 0 and the "sum++", increase the value of the sum by 1.
  • So the value of the sum becomes 10 after completing 10 iterations of the inner for loop.
  • Hence the 10 will be the output. So the Option d is the correct answer while the other is not.
3 0
3 years ago
How do you fix The lag on your zsnes emulator
GenaCL600 [577]
Try resetting the phone if that doesn’t work do a hard reset
7 0
3 years ago
JAVA
qwelly [4]

public class MyClass {

   public static void main(String args[]) {

     int x = 1;

     int total = 0;

     for (int i = 1; i <= 10; i++){

         x *= i;

         total += x;

     }

     System.out.println(total);

   }

}

This program finds the sum of that series to the tenth term, the sum is: 4037913. I hope this helps.

6 0
3 years ago
Question # 1
MA_775_DIABLO [31]

Answer:

an error statement since total's scope is limited to the average function.

Explanation:

The scope of total is the function average. Code outside of the function does not have access to its value.

Correct answer edge 2020

7 0
3 years ago
Read 2 more answers
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