Answer:
Answered below
Explanation:
Class BaseballPlayer{
//Instance variables
string name;
int hits;
int bats;
//Constructor
BaseballPlayer (string a, int b, int c){
name = a;
hits = b;
bats = c
}
public void printBattingDetails( ){
System.out.print(name, hits, bats)
}
}
//Demo class
Class BaseballTester{
public static void main (String args []){
BaseballPlayer player = new BaseballPlayer("Joe", 8, 4)
player.printBattingDetails( )
}
}
Answer:It will decrease harmful emissions, so the factories will no longer need to install them.
Explanation:
This helps improve the safety of the surrounding community and workers. But this technology is expensive and required time and effort to install.
Oh that is easy first they differ the therms of their ability and that helps them process the information ( sorry for doing that lol)
Answer:
import random
import math
smaller = int(input("Enter the smaller number: "))
larger = int(input("Enter the larger number: "))
count = 0
print()
while True:
count += 1
myNumber = (smaller + larger)
print('%d %d' % (smaller, larger))
print('Your number is %d' % myNumber)
choice = input('Enter =, <, or >: ')
if choice == '=':
print("Hooray, I've got it in %d tries" % count)
break
elif smaller == larger:
print("I'm out of guesses, and you cheated")
break
elif choice == '<':
larger = myNumber - 1
else:
smaller = myNumber + 1
Explanation:
- Inside an infinite while loop, add the smaller and larger number and assign that value to myNumber variable.
- Check the choice and then print the relevant display message.
Answer:
00100110
a and d are invalid sequences because they contain an even number of 1's.
Explanation:
Odd parity means that you want an odd number of 1's in the resulting set of bits. Since there are 3 (=odd) bits in the set, a zero must be added to keep the total odd.
