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Burka [1]
3 years ago
10

Factor completely 2x3 + x2 - 18x - 9

Mathematics
2 answers:
melisa1 [442]3 years ago
7 0
Factor the following:
2 x^3 + x^2 - 18 x - 9

Factor terms by grouping. 2 x^3 + x^2 - 18 x - 9 = (2 x^3 + x^2) + (-18 x - 9) = x^2 (2 x + 1) - 9 (2 x + 1):
x^2 (2 x + 1) - 9 (2 x + 1)

Factor 2 x + 1 from x^2 (2 x + 1) - 9 (2 x + 1):
(2 x + 1) (x^2 - 9)

x^2 - 9 = x^2 - 3^2:
(2 x + 1) (x^2 - 3^2)

Factor the difference of two squares. x^2 - 3^2 = (x - 3) (x + 3):

Answer:  (x - 3) (x + 3) (2 x + 1) thus the Answer is C.
Contact [7]3 years ago
4 0

Answer:

(x - 3) (x + 3) (2 x + 1) thus the Answer is C.

Step-by-step explanation:

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Shade the model to show the decimal 0.542 using 100 grid and 10 grid
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3 years ago
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Reggie earns $12.65 per hour and works 38 hours per week. How much does he warm in a week before taxes are taken out?
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3 years ago
Two angles in a triangle measure (2.3x+25)° and (5.8x+11)°. what is the value of x if the two angles are congruent to one anothe
Anton [14]

Answer:

The answer is D. x= 4

Step-by-step explanation:

The angles are congruent so

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2.3x - 5.8x = 11 - 25

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3 years ago
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If (ax^2 + 3x + 2b) - (5x^2+bx-3c)=3x^2-9, what is the value of A + B + C?
Rina8888 [55]

Answer:

We have the equation:

(ax^2 + 3x + 2b) - (5x^2+bx-3c)=  3x^2 - 9

First, move all to the left side.

(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0

Now let's group togheter terms with the same power of x.

(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.

This must be zero for all the values of x, then the things inside each parenthesis must be zero.

1)

a - 5 - 3 = 0

a = 3 + 5 = 8.

2)

3 - b = 0

b = 3.

3)

2b + 3c + 9 = 0

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3c = -6 - 9 = -15

c = -15/3 = -5

Then we have:

a = 8, b = 3, c = -5

a + b + c = 8 + 3 - 5 = 6

8 0
3 years ago
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