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Leya [2.2K]
3 years ago
7

HELP ME PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! :3

Mathematics
1 answer:
crimeas [40]3 years ago
8 0

Answer:

To write an equation in slope-intercept form, given a graph of that equation, pick two points on the line and use them to find the slope. This is the value of m in the equation. Next, find the coordinates of the y-intercept--this should be of the form (0, b). The y- coordinate is the value of b in the equation.

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AnnyKZ [126]

Answer:

Which ones you need help with? All of it?

Step-by-step explanation:

8 0
3 years ago
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Find the slope of the line that passes through (10, 8) and (9, 13)
7nadin3 [17]
Slope is 5!

Equation:
13-8/9-10=5/1

y2-y1=x2-x1
3 0
3 years ago
For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
3 years ago
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I going with A hope that helps
7 0
3 years ago
If 1 pound of candy is 3.50 how much candy can you get with one dollar?
polet [3.4K]

Answer:

Step-by-step explanation:

16 divided by $3.50 = 4.5

4 0
3 years ago
Read 2 more answers
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