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7nadin3 [17]
3 years ago
11

I need help

Mathematics
1 answer:
ankoles [38]3 years ago
6 0
Your answer would be y + 9 = m(x + 6)
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Please help me ASAP​
Serggg [28]

The class 4S because you divide each number by its mean mark and standard division and 4S is the highest.

5 0
3 years ago
Please help me I really need this and show your work if possible
kogti [31]
The temperature at 9 am was -11 degrees.

We know that at 5 am, it was -7 degrees. Since the change of temperature is a negative number, then we subtract the absolute value of the change from -7. -7 - 3 = -10. Following this pattern, we then have:
-10 - 2 = -12 (6 am - 7 am)
-12 - 5 = -17 (7 am - 8 am)
-17 + 6 = -11 (8 am - 9 am, added since it was a positive change of temperature)

And our final answer is -11 degrees Fahrenheit.
5 0
3 years ago
Read 2 more answers
If the mountain at a convergent plate boundary is growing at a rate of 1.6 mm per year, how much higher will it be in 50 years ?
Mrrafil [7]
The mountain will be at 80mm long in 50 years because 50 times 1.6mm equals 80
5 0
3 years ago
Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

hypotenuse^2=25+144

hypotenuse^2=169

Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
4 years ago
What is the answer to 7f/11 =7/11
serious [3.7K]
So,

\frac{7f}{11} =  \frac{7}{11}

Multiply both sides by 11.
7f = 7

Divide both sides by 7.
f = 1

Check.
\frac{7(1)}{11} =  \frac{7}{11}
\frac{7}{11} =  \frac{7}{11} This checks.

S = {1}
5 0
3 years ago
Read 2 more answers
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