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spin [16.1K]
3 years ago
14

Do you know 3/4 divided by 1/3=??

Mathematics
2 answers:
Tresset [83]3 years ago
7 0
That would be 9/4

Or in mixed number form: 2 1/4

I hope this helps! (:
KIM [24]3 years ago
4 0
If you divide using the rule of four, the answer is 3 1/4.
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Use a calculator to evaluate cot pi/5
Dovator [93]
It is about <span>1.37638192. 
The cotangent is just one divided by the tangent. So, find the tangent of pi/5 = </span><span>0.726542528, then divide 1 by that number.</span>
6 0
4 years ago
Two students, X and Y, forgot to put their names on their exam papers. The professor knows that these two students do well on th
Luda [366]

Answer:

The probability that the good exam belongs to student <em>X</em> is 0.8571.

Step-by-step explanation:

It is provided that the probability that <em>X</em> did well in the exam is, P (X) = 0.90 and the probability that <em>X</em> did well in the exam is, P (Y) = 0.40,

Compute the probability that exactly one student does well in the exam as follows:

P(Either\ X\ or\ Y\ did\ well)=P(X\cap Y^{c})+P(X^{c}\cap Y)\\=P(X)P(Y^{c})+P(X^{c})P(Y)\\=P(X)[1-P(Y)]+[1-P(X)]P(Y)\\=(0.80\times0.60)+(0.20\times0.40)\\=0.56

Then the probability that <em>X</em> is the one who did well in the exam is:

P(X\ did\ well\ in\ the\ exam)=\frac{P(X\cap Y^{c})}{P(X\cap Y^{c})+P(X^{c}\cap Y)}\\ =\frac{P(X)[1-P(Y)]}{P(X\cap Y^{c})+P(X^{c}\cap Y)} \\=\frac{0.80\times0.60}{0.56}\\=0.857143\\\approx0.8571

Thus, the probability that the good exam belongs to student <em>X</em> is 0.8571.

8 0
3 years ago
Help me please! <br> thank you!
Trava [24]
The simpilest form will be A. Hope this helps :)
8 0
3 years ago
Tony's taking cookies to a bake sale. He already made 70 cookies on Monday, and wants to make more on Tuesday. His plan allows h
kotegsom [21]
70+14 x 7 =168 :-]  :-]  :-]

6 0
3 years ago
CLASS PROJECT An economics class formed a company to sell school supplies. They would like to sell at least 20 notebooks and 50
lesya692 [45]

Answer:

60≥20x+50y

Step-by-step explanation:

Let x = notebooks and y = pens (all per week)

One solution would be x ≥ 1 and y ≥ 1 as at least one per each item per week

8 0
3 years ago
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