The fourth class ends at 12:30 pm
<em><u>Solution:</u></em>
Given that Harold has 4 classes each morning
Each class is 1 hour long, and there are 10 minutes between classes
The first class is at 8 A.M
<em><u>To find: Time at which fourth class ends</u></em>
Since each is 1 hour long and 10 minutes gap between classes
First class = 8 A.M to 9 A.M
Second class = 9:10 A.M to 10 : 10 AM
Third class = 10 : 20 AM to 11 : 20 AM
Fourth class = 11 : 30 AM to 12 : 30 PM
Thus the fourth class ends at 12:30 pm
Volume of the cylinder=area (circle) x height
area (circle)=πr²
r=radius=4 in.
area=π(4 in)²=16π in²
height=8 in
Volume of the cylinder=(16π in²)(8 in)=128π in³≈402.12 in³
Answer= 128π in³ or 402.12 in³
Answer:
4
Step-by-step explanation:
The y-variable can be eliminated by adding 3 times the first equation to the second:
3(2x -y) +(x +3y) = 3(11) +(-5)
7x = 28 . . . . simplify
x = 4 . . . . . . . divide by 7
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Using Cramer's Rule, you can also find the x-value. The math is not so different.
x = ((-1)(-5) -(3)(11))/(-1(1) -3(2)) = -28/-7 = 4
First combine like terms and put the expression in standard form. This expression is now in simplest form and cannot be simplified anymore.
3a + 10ab - 7a^2b - 10ab^2 + 12ab - (-4) + (-a^2b) - 5a
-10ab^2 - 8a^2b -2a + 24ab - (-4)
Hope this helps
Answer:
f(d)=400(0.794)^d
Step-by-step explanation:
