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gizmo_the_mogwai [7]
3 years ago
5

11.447 is greater than 11.473

Mathematics
1 answer:
Stells [14]3 years ago
8 0
No 11.473 is greater then 11.447
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What is the value of x in the equation 1.5(x + 4) – 3 = 4.5(x – 2)?
Pepsi [2]
X=4
Step 1: Simplify both sides of the equation.
1.5(x+4)-3=4.5(x-2)
(1.5)(x)+(1.5)(4)+ -3 =(4.5)(x)+(4.5)(-2)
(1.5x) + ( 6+-3) =4.5x - 9
(Combine like terms)
1.5x+3=4.5x-9

Step 2: Subtract 4.5x from both sides.
1.5x +3 -4.5x =4.5x=-9-4.5x-3x+3=-9

Step 3: Subtract 3 from both sides.
-3x+3-3=-9-3
-3x=12

Step 4: Divide both by -3
-3x/-3=-12/-3
X=4
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3 years ago
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A. 18 - 25 because 29% plus 23% equals 52%


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How many ways can a person toss a coin 13 times so that the number of tails is between 7 and 11 inclusive?
lilavasa [31]
What are the choices?
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3 years ago
Which relation is not a function? Reporting wrong answers.
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2 years ago
Suppose you are given information about a triangle according to SSS, SAS, and ASA. For which of these can you immediately use th
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Answer:

SSS and SAS

Step-by-step explanation:

Law of cosines: The law of cosines is used for calculating one side of a triangle when the angle opposite and the other two sides are known.

If the information about a triangle according to SSS, SAS and ASA is given, then we will immediately use SSS and SAS  by using the law of cosines to find one of the remaining measures because Law of cosines is applied if we know one angle opposite and the other two sides.

Also, in ASA, we know two angles and one side, thus we cannot use Law of cosines in this, rather Law of sines can be accurately use in this case.

if you have two sides, encroaching an angle, then the Law of Cosines can be used to find a missing side, thus SAS will work fine for that, now, if you have no angles given, but you know all sides, you can use the Law of Cosines as well, by solving it for the angle, and get the angles, on which case, SSS will do... .now as far as ASA, if you have two angles and one side known, then... that's not very workable for the law of cosines

please mark me brainliest :)

3 0
3 years ago
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