The distances from D to the both sides(AB and AC) of the triangle are 4 ft.
<u><em>Explanation</em></u>
In the diagram below, ABC is a triangle in which ∠CAB = 60°
As, AD is the angle bisector of ∠CAB, that means ∠CAD = ∠DAB = 30°
The distance from D to side AC is DE and distance from D to side AB is DF. That means both ∠AED and ∠AFD are right angle.
Given that, the length of AD = 8 ft.
So, in right angle triangle AED.....
![sin(30)= \frac{DE}{AD}\\ \\ sin(30)= \frac{DE}{8} \\ \\ \frac{1}{2}= \frac{DE}{8}\\ \\ 2*DE=8\\ \\ DE=4](https://tex.z-dn.net/?f=sin%2830%29%3D%20%5Cfrac%7BDE%7D%7BAD%7D%5C%5C%20%5C%5C%20sin%2830%29%3D%20%5Cfrac%7BDE%7D%7B8%7D%20%5C%5C%20%5C%5C%20%5Cfrac%7B1%7D%7B2%7D%3D%20%5Cfrac%7BDE%7D%7B8%7D%5C%5C%20%5C%5C%202%2ADE%3D8%5C%5C%20%5C%5C%20DE%3D4)
Also, in right angle triangle AFD....
![sin(30)= \frac{DF}{AD}\\ \\ sin(30)= \frac{DF}{8} \\ \\ \frac{1}{2}= \frac{DF}{8}\\ \\ 2*DF=8\\ \\ DF=4](https://tex.z-dn.net/?f=sin%2830%29%3D%20%5Cfrac%7BDF%7D%7BAD%7D%5C%5C%20%5C%5C%20sin%2830%29%3D%20%5Cfrac%7BDF%7D%7B8%7D%20%5C%5C%20%5C%5C%20%5Cfrac%7B1%7D%7B2%7D%3D%20%5Cfrac%7BDF%7D%7B8%7D%5C%5C%20%5C%5C%202%2ADF%3D8%5C%5C%20%5C%5C%20DF%3D4)
So, the distances from D to the both sides(AB and AC) of the triangle are 4 ft.
You gotta post a picture of the graph
164 times 5 is 820. 824 minus 820 is 4. Therefore there will be 4 marbles left
Answer:
25.5 is the answer!!!!!!!!!!!!!