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Phoenix [80]
2 years ago
13

Write an equation and solve for x

Mathematics
1 answer:
user100 [1]2 years ago
8 0
3x+12+x=90, simplify (4x+12=90), subtract both sides by 12 (4x=78), divide both sides by 4 (39/7)
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Elaine had 5/8 of a pizza left after lunch. She told 5 of her friends that they could share the rest. What fraction of the pizza
Oduvanchick [21]

Answer:

1/8

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A laptop is sold for $1274 after a discount of 9%.
chubhunter [2.5K]

Answer:

SP = 1274

Discount 9%

Selling price = MP (100 - d) / 100

1274 = MP (100 - 9) / 100

1) MP = 1400

i) After 5% discount = 1400 x 0.95 = 1330

After 4% discount = 1330 x 0.96 = 1276.80

3 0
3 years ago
How many litres of milk can be put in six hemispherical bowl each of diameter 35cm​
Lesechka [4]

Answer:

Approximately 67.348 litres can be put in six hemispherical bowl with a diameter of 35 centimetres.

Step-by-step explanation:

The volume of a hemisphere (V), measured in cubic centimetres, is obtained from this formula:

V = \frac{2\pi}{3}\cdot R^{3}

Where R is the radius of the hemisphere, measured in centimetres.

We know that radius is the half of the diameter (D), measured in centimetres, then:

R = 0.5\cdot D

(D = 35\,cm)

R = 0.5\cdot (35\,cm)

R = 17.5\,cm

Now, we get the volume of each hemispherical bowl:

V = \frac{2\pi}{3} \cdot (17.5\,cm)^{3}

V \approx 11224.649\,cm^{3}

The total volume of six hemispherical bowl is:

V_{T} = 6\cdot V

V_{T}= 6\cdot (11224.649\,cm^{3})

V_{T} = 67347.894\,cm^{3}

From Physics we know that 1 litre equals 1000 cubic centimetres. Then:

V_{T} = 67.348\,L

Approximately 67.348 litres can be put in six hemispherical bowl with a diameter of 35 centimetres.

3 0
3 years ago
Evaluate.<br><br> 1+5⋅32<br><br> A. 8<br><br> b. 9<br><br> c. 16<br><br> d.18
Anna007 [38]

Answer:

the answer should be 161

6 0
3 years ago
Your teacher announced a 50-point math quiz for tomorrow. The quiz will have 15 questions with word problems worth 4 points each
koban [17]

Answer:

5  word problems(4points each)      &      10 open (3 points each)

Step-by-step explanation:

O= open response

W= word problems

  W+O =15

4W + 3O = 50

multiply the first by -3 to eliminate O

-3W -3O = -45

4W  + 3O = 50

  AD BOTH

W = 5    ( 5 questions word problems)

O= 10   ( 10 questions open response)

  5x4 = 20

10x3 = 30

      20 + 30 = 50 points

3 0
2 years ago
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