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Yuliya22 [10]
3 years ago
12

What is the solution to y-7>3+2y

Mathematics
1 answer:
Alex17521 [72]3 years ago
6 0

Solving:

-7 + y = 3 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.

-7 + y + -2y = 3 + 2y + -2y

Combine like terms: y + -2y = -1y

-7 + -1y = 3 + 2y + -2y

Combine like terms: 2y + -2y = 0

-7 + -1y = 3 + 0

-7 + -1y = 3

Add '7' to each side of the equation.

-7 + 7 + -1y = 3 + 7

Combine like terms: -7 + 7 = 0

0 + -1y = 3 + 7

-1y = 3 + 7

Combine like terms: 3 + 7 = 10

-1y = 10

Divide each side by '-1'.

y = -10

Hope it helps. (:

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Step-by-step explanation:

22 is the largest number you are given in this diagram. 0 is the smallest. that would be your first step.

Next think about it as if you already know your midpoint, as in, midpoint being half of your ending value.

Lastly, you want to divide 22 in half, since midpoint is half of your line segment, and then answer you get is 11

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Round 48.078 to the nearest tenth
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Step-by-step explanation:

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ANSWER: 50

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You estimated the average rental cost of a 2 bedroom apartment in Denton. A random sample of 16 apartments was taken. The sample
Zigmanuir [339]

Answer:

The new sample size required in order to have the same confidence 95% and reduce the margin of erro to $60 is:

n=28

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma=160)  

And the distribution for \bar X is:

\bar X \sim N(\mu, \frac{160}{\sqrt{n}})  

We know that the margin of error for a confidence interval is given by:  

Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)  

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.95=0.05 and \alpha/2=0.025  

Using the normal standard table, excel or a calculator we see that:  

z_{\alpha/2}=\pm 1.96  

If we solve for n from formula (1) we got:  

\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}  

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And we have everything to replace into the formula:  

n=(\frac{1.96(160)}{78.4})^2 =16  

And this value agrees with the sample size given.

For the case of the problem we ar einterested on Me= $60, and we need to find the new sample size required to mantain the confidence level at 95%. We know that n is given by this formula:

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And now we can replace the new value of Me and see what we got, like this:

n=(\frac{1.96*160}{60})^2 =27.32

And if we round up the answer we see that the value of n to ensure the margin of error required Me=\pm 60 $ is n=28.    

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Answer:

Irrational:

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Step-by-step explanation:

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