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3 years ago

What is the value of y for the line that had a slope of -3/2 and passes through the points (3,5) and (7,y)?

1 answer:

7 0

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{y}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{y-5}{7-3}=\stackrel{\stackrel{slope}{\downarrow }}{-\cfrac{3}{2}}\implies \cfrac{y-5}{4}=-\cfrac{3}{2} \\\\\\ 2y-10=-3y\implies 5y-10=0\implies 5y=10\implies y=\cfrac{10}{5}\implies y=2$

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Basile [38]

Answer:

Step-by-step explanation:

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3 years ago

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Olegator [25]

Answer:

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Step-by-step explanation:

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3 years ago

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Which of the following describes the graph of y=\sqrt(-4x-36) compared to the parent square root function?

borishaifa [10]

Answer:

Option D - Stretched by a factor of 2, reflected over the y-axis, and translated 9 units left.

Step-by-step explanation:

Given : The function $y=\sqrt{-4x-36}$

To find : Which of the following describes the graph of $y=\sqrt{-4x-36}$ compared to the parent square root function?

Solution :

First we simplify the given expression

$y=\sqrt{-4x-36}$

$y=\sqrt{4(-x-9)}$

$y=2\sqrt{-(x+9)}$

→When we see the original square root function minus was taken outside x and 9 was added from x and 2 was multiplied to the entire function.

Multiplying 2 in the function will give you the stretched by a factor of 2.

$g(x)=\sqrt{-x}$ shows the reflection about y-axis i.e, (x,y)→(-x,y).

If f(x)→f(x+b) then function is shifted left by unit b

⇒ g(x))→g(x+9) then function is shifted left by unit 9

Therefore, The graph of was stretched by a factor of 2, reflected over the y-axis, and translated 9 units left to obtain the graph of the function .

So, Option D is correct.

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3 years ago

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The figure shows triangle PQR and some of its transformed images on a coordinate grid:

tangare [24]

A and b for a while lol

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2 years ago

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Find the product. (r s)2 r² 2rs s r² 2rs s² r² 2rs 2s².

sveta [45]

The product of the given expression is $\rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs$ .

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The product of $\rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2$ .

<h3>What is multiplication?</h3>

Multiplication is the process of calculating the product of two or more numbers.

The multiplication of numbers say, ‘a’ and ‘b’, is stated as ‘a’ multiplied by ‘b’.

The product of $\rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2$ is given by;

$\rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2\\\\(2r^3 + 2r^2s) + 2rs + 2rs + 2rs + s^2r^2 + sr^2 + 2s^2\\\\2r^3+ 2r^2s + 6rs + s^2r^2 + sr^2+ 2s^2$

$\rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs$

Hence, the product of the given expression is $\rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs$ .

To know more about Multiplication click the link given below.

brainly.com/question/19943359

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2 years ago