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Sauron [17]
3 years ago
14

Which expression is equivalent to (2x^5 + 7x^3) - (5x^2 - 4x^3)

Mathematics
1 answer:
Basile [38]3 years ago
6 0

Answer:

= 2x^{5} +11x^{3}-5x^{2}

0r

= -5x^{2} +11x^{3}+2x^{5}

Step-by-step explanation:

(2x^{5} +7x^{3} )-(5x^{2}-4x^{3}  )

= 2x^{5} +7x^{3} -5x^{2}+4x^{3}

= 2x^{5} +7x^{3} +4x^{3}-5x^{2}

= 2x^{5} +11x^{3}-5x^{2}

0r

= -5x^{2} +11x^{3}+2x^{5}

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Kryger [21]

Answer:

Step-by-step explanation:

A. k/5 = 3:  Isolate k by multiplying both sides of this equation by 5:

k = 15

       

B. 3.5d = 70;  Divide both sides by 3.5, obtaining d = 20

C. 4 1/2 = 1 1/2n;   Rewrite 4 1/2 and 1 1/2 as improper fractions:

  9/2 = (3/2)n.  Now multiply both sides by (2/3):  3 = n

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Artemon [7]

\huge\text{Hey there!}

\large\text{What is }\mathsf{\dfrac{31}{5}}\large\text{ ?}

\large\text{In order for you to solve for this equation you have to DIVIDE}\\\large\text{the NUMERATOR (the TOP number) from the DENOMINATOR}\\\large\text{(the BOTTOM number)}

\mathsf{\dfrac{31}{5}=31\div5\rightarrow \bf 6\ with\ a\ remainder\ of\ 1. \ (6\ r\ 1)}

\large\text{Thus, }\mathsf{\dfrac{31}{5}}\large\text{ is equivalent or equal to }\mathsf{6\dfrac{1}{5}}

\boxed{\boxed{\mathsf{Answer: \bf 6\dfrac{1}{5}}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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3 years ago
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