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NNADVOKAT [17]
3 years ago
14

I need help with this question

Mathematics
2 answers:
zloy xaker [14]3 years ago
8 0
The answer to this is a.
S_A_V [24]3 years ago
8 0

The answer is "A" because sum means the answer of addition problem.

example. the sum of 2 and 4, that means 2+4

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I believe it is 56 square inches
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Write an equation in slope-intercept form for the line with slope-4 and y-intercept -1
Drupady [299]

Answer:

y = -4x - 1

Step-by-step explanation:

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IS 3.
coldgirl [10]

Answer:

1. a. 2,000

2. b. 10 years

3. a. 6.72937

4. d. 9%

Step-by-step explanation:

1. If 58% are boys, the percentage of girls is:

= 100 - 58

= 42%

That means 840 is 42% of the students in class. The students in class are therefore:

= 840 / 42%

= 2,000 students

2. If Birr 300 is invested at 6% per year, the amount in interest it earns per year is:

= 300 * 6%

= Birr 18

To get to Birr 180, it would take:

= 180/18

= 10 years

3. When a number is in percentage that means that it is a fraction with the denominator being 100. The number is decimal will therefore be it divided by 100:

= 672.937/100

= 6.72937

4. The investment accrued Birr 12 out of Birr 400 in 4 months. This means that it increased by:

= 12/400

= 3%

A year can be divided into three by 4 months. This means that the yearly rate is therefore:

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6 0
3 years ago
In this question, i is a unit vector due east and j is a unit vector due north. A cyclist rides at a speed of 4 m/s on a bearing
d1i1m1o1n [39]

<u>Answer:</u>

a) 1.04i + 3.86j

b) magnitude = 8; bearing = 302.7°

<u>Step-by-step explanation:</u>

a)

The  first diagram represents the velocity vector of the cyclist.

To express this vector in the form xi + yj, we have to find the components of the vector in the horizontal (i) and vertical (j) directions.

If we consider the horizontal component of the vector to be x, and the vertical component to be y, then:

• horizontal component ⇒ sin (15^{\circ}) = \frac{x}{4}

                                       ⇒ x = 4\space\ sin(15^{\circ})

                                       ⇒ x \approx \bf 1.04

• vertical component ⇒ cos(15^{\circ}) = \frac{y}{4}

                                   ⇒ y = 4 \space\ cos(15^{\circ})

                                   ⇒ y \approx \bf 3.86

Now that we have the values of both the horizontal and vertical component, we can write the vector in the form of xi + yj:

vector ⇒ 1.04i + 3.86j

b)

The second diagram shows the first vector (red), the second vector (blue), and the resultant vector <em>v</em> (black). The dashed lines represent the components of the respective vectors.

To add two vectors given their magnitudes and direction, we have to add their components.

In order to find the horizontal and vertical components of the given vectors, we can use a method similar to that used above, so that:

○ For the first vector (magnitude 6):

• horizontal component ⇒ x = 6 \space\ sin (60^{\circ})

                                       ⇒ \bf 5.2

• vertical component ⇒ y = 6 \space\ cos(60^{\circ})

                                   ⇒ y = \bf 3

○ For the second vector (magnitude 2):

• horizontal component ⇒ x = 2 \space\ cos (40^{\circ})

                                       ⇒ \bf 1.5

• vertical component ⇒ y = 2 \space\ sin(40^{\circ})

                                   ⇒ \bf 1.3

Now we can add the respective components together:

v = 5.2i + 3j  +  1.5i + 1.3j

 ⇒ (5.2 + 1.5)i + (3 + 1.3)j

 ⇒  6.7i + 4.3j

∴ Magnitude of v ⇒ |v| = \sqrt{(6.7)^2 + (4.3)^2}

                             ⇒ |v| \approx \bf 8

To find the bearing of <em>v</em>, we have to first calculate the angle marked \alpha:

tan \alpha = \frac{4.3}{6.7}

⇒ \alpha = tan^{-1}(\frac{4.3}{6.7})

⇒ \alpha = \bf 32.7^{\circ}

∴ Bearing = 270° + 32.7°

                = 302.7°

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