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Mila [183]
4 years ago
15

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 4%. If the rate of deca

y is proportional to the amount of the substance present at time t, find the amount remaining after 24 hours. (Round your answer to one decimal place.)
Mathematics
1 answer:
11111nata11111 [884]4 years ago
5 0

Answer:

84.96 mg

Step-by-step explanation:

No = 100 mg

t = 6 hours, N = 96% of No = 96 / 100 No

t = 24 hours, N = ?

Let after 24 hours the remaining part is N.

Use the decay law equation

N = No e^-λt

96 / 100 = e^-6λ  

0.96 = e^-6λ

taking natural log on both the sides

ln 0.96 = - 6λ

λ = 6.8 x 10^-3 per hour

Now,

N = No e^-24λ

N = No x e^-(24 x 6.8 x 10^-3)

N = No (0.8496)

N = 100 x 0.8496 = 84.96 mg

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Step-by-step explanation:

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Suppose the actual yield is of 80 and the theoretical yield is of 100. We want to, for example, know the percentage of the yield. First we divide 80 by 100, which is 0.8, a decimal value. To write as a percentage, we multiply it by 100.

So the correct answer is:

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construct a 90% confidence interval of the population proportion using the giver information x=74 n=150
FrozenT [24]

Answer:

The 90% confidence interval of the population proportion is (0.43, 0.56).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

The information provided is:

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<em>n</em> = 150

Confidence level = 90%

Compute the value of sample proportion as follows:

\hat p=\frac{X}{n}=\frac{74}{150}=0.493

Compute the critical value of <em>z</em> for 90% confidence level as follows:

z_{\alpha/2}=z_{0.10/2}=z_{0.05}=1.645

*Use a <em>z</em>-table.

Compute the 90% confidence interval of the population proportion as follows:

CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.493\pm 1.645\times \sqrt{\frac{0.493(1-0.493)}{150}}\\\\=0.493\pm 0.0672\\\\=(0.4258,\ 0.5602)\\\\\approx (0.43,\ 0.56)

Thus, the 90% confidence interval of the population proportion is (0.43, 0.56).

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