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svetlana [45]
3 years ago
7

Solve the following equation for x: 5x + 3y = 15.

Mathematics
1 answer:
zepelin [54]3 years ago
8 0

Answer:

B) x = (-3/5)y + 3

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

first, subtract 3y from btoh sides:

5x + 3y (-3y) = 15 (-3y)

5x = -3y + 15

Next, divide 5 from both sides:

(5x)/5 = (-3y +15)/5

x = (-3/5)y + 3

B) x = (-3/5)y + 3 is your answer.

~

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Given that f(x) = x + 3<br> a) Find f(2)
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{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

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\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

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\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

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