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svetlana [45]
3 years ago
7

Solve the following equation for x: 5x + 3y = 15.

Mathematics
1 answer:
zepelin [54]3 years ago
8 0

Answer:

B) x = (-3/5)y + 3

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

first, subtract 3y from btoh sides:

5x + 3y (-3y) = 15 (-3y)

5x = -3y + 15

Next, divide 5 from both sides:

(5x)/5 = (-3y +15)/5

x = (-3/5)y + 3

B) x = (-3/5)y + 3 is your answer.

~

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-7v² - 57v - 2

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A researcher posts an online advertisement offering $25 in exchange for participation in a short study. The researcher accepts t
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A computer programmer's yearly income of $82,000 is increased by 6%. What is the dollar amount of the increase, and what is her
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Write the equation of the line that passes through (-6,0) and is parallel to the line y=5x-43
AVprozaik [17]

The equation of the line that passes through (-6,0) and is parallel to the line y = 5x - 43 in slope intercept is y = 5x + 30

<em><u>Solution:</u></em>

Given that line that passes through (-6, 0) and is parallel to the line y = 5x - 43

We have to find the equation of line

Let us first find slope of line having equation y = 5x - 43

<em><u>The slope intercept form of line is given as:</u></em>

y = mx + c  ------- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing equation of line y = 5x - 43 with slope intercept form y = mx + c,

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Thus the slope of line parallel to given line is also 5

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Substitute m = 5 and (x, y) = (-6, 0) in eqn 1

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0 = 5(-6) + c

<h3>c = 30</h3>

<em><u>Thus the required equation is:</u></em>

Substitute c = 30 and m = 5 in eqn 1

y = 5x + 30

Thus the required equation of line is found

8 0
3 years ago
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