Answer:
40
Step-by-step explanation:
- Use the rules of PEMDAS: 48 ÷ 6 = 8
- Plug 8 in: 64 - 8 × 4 + 8
- 8 × 4 = 32
- Plug 32 in: 64 - 32 + 8
- 64 - 32 = 32
- Plug 32: 32 + 8
- 32 + 8 = 40
I hope this helps!
2 consecutive odd positive integers....x and x + 2
x^2 + (x + 2)^2 = 130
x^2 + (x + 2)(x + 2) = 130
x^2 + x^2 + 4x + 4 = 130
2x^2 + 4x + 4 = 130
2x^2 + 4x + 4 - 130 = 0
2x^2 + 4x - 126 = 0
2(x^2 + 2x - 63) = 0
2(x - 7)(x + 9) = 0
x - 7 = 0
x = 7
x + 9 = 0
x = -9 (cant be this one because it is negative
so x = 7...and x + 2 = 7 + 2 = 9......ur 2 numbers are 7 and 9
Answer:
2x ^5 sqrt( 6x)
Step-by-step explanation:
sqrt( 3 x^4) * sqrt( 8 x^7)
Multiply them together
sqrt( 3x^4 * 8x^7)
sqrt( 24 x^ (4+7))
sqrt( 24 x^11)
We can simplify
sqrt(24) sqrt(x^11)
sqrt( 4*6) sqrt( x^10) sqrt(x)
sqrt(4) sqrt(6) x^5sqrt(x)
2 sqrt(6) x^5sqrt( x)
Combining the square roots
2x ^5 sqrt( 6x)
I believe it would be this:
3 (2×-5)=1+4× 6-15=1+4× 6×=1+4×+15
I hope this answer helped, and my deepest apologies if I have calculated wrongly. Math is tricky! :)
The answer is b. see pic for answer