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love history [14]

3 years ago

13

consider the following systems of linear inequalities. x+2y is > than or equal to 10 and 3x-4y>12. Which of the following

ordered pairs are solutions to the system

1 answer:

Neporo4naja [7]3 years ago

5 0

The answer is (10,2),(14,-1), and (8,1)

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andrew-mc [135]

Answer:

1) $\frac{1}{2^7}$ ; 2) $11^7$

Step-by-step explanation:

1) Using the Power of a Fraction Rule $(\frac{a}{b} )^x = (\frac{a^x}{b^x} )$ ,

$(\frac{1}{2} )^7 = (\frac{1^7}{2^7} )$ , which can just be simplified to $\frac{1}{2^7}$ .

2) Using the Negative Exponent Rule, $a^{-x} = \frac{1}{a^{x}}$ ,

$(\frac{1}{11} )^{-7} = \frac{1}{\frac{1}{11^7}}$ , which can be simplified to $11^7$ .

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3 years ago