In the triangle, the fact that wee are given 2AX = 3XD isn't enough to prove similarity.
<h3>How to explain the triangle?</h3>
a. In the question, we are given 2AX = 3XD. An arbitrary triangle AXB can be drawn where one extends AX and choose a point D on the extended line in order for 2AX = 3XD. Also, extend BX and choose a point C on the line so that 2BX = XC. Even though they both satisfy the condition, they're not similar.
b. We are given that AX/BX = DX/CX. When this is rearranged, we'll have AX/DX = BX/CX. In this case, let AX/DX = k. DX and AX will align upon rotation of 180°. The triangle can then be dilated by a factor of k. This brings about the mapping of triangle DXC to AXB. Therefore, the original triangle DXC is similar to AXB.
c. Lines AB and CD are parallel. Here, the dilation moves line CD onto line AB. Here, since the dilation moves D to a point on ray XA, D must move to A. Therefore, the rotation of triangle DXC is similar to AXB. Therefore, DXC is similar to AXB.
d. Here, angle XAB is congruent to angle XCD. This shows similarity and in this case, XCD is similar to XAB.
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Answer:
12.5a-8.1b
Step-by-step explanation:
Remove the unnecessary parenthesis
14.2+9.8b-(13.1b-2a)-(3.7a+4.8b)
Collect like terms
12.5a+9.8b-13.1b-4.8b
Giving you the answer of: 12.5a-8.1b
(−)⋅2−(+)⋅+2
2−2−(+b)⋅x+2
2−2−(+)⋅+2
2−2−−+2
2−2−−+2
<h3>Answers:</h3><h3>There are four solutions and they are</h3>
... this says "7pi over 6"
... this says "11pi over 6"
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Work Shown:
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Solving 
leads to 
for any integer n.
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Solving 
leads to...
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The general solution set is
Again, n is any integer.
Let's look at a table of values where we plug in various integers for n. See the attached image below. Note the stuff in the highlighted yellow cells represents expressions that are between 0 and 2pi = 6.28
Therefore the four solutions are 
after we plug the proper values of n into the expressions, to have things match what the table shows.
Answer: most likely the second and last
Step-by-step explanation:
