Answer:
Step-by-step explanation:
Answer:
(x + 3)² + y² = 16
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Here (h, k) = (- 3, 0 ) and r = 4, thus
(x - (- 3))² + (y - 0)² = 4², that is
(x + 3)² + y² = 16
Answer: 6(x-2)
Step-by-step explanation:
(x·2-8)-(2x·2+4)
(2(x-4))+2x·2-4
2(x-4)+2x·2-4
2(x-4)+4x-4
2(x-4+2x-2)
2(3x-4-2)
2(3x-6)
2·3(x-2)
6(x-2)
Answer:
7.5s
1.6666 repeating or 1.67 m/s²
Step-by-step explanation:
the equation you have to use is Vfinal=Vstart+acceleration•time
(I'm gonna simplify to Vf=Vs+at)
so you gotta rework it for the two equations
for the first equation you need time so take Vf=Vs+at and subtract Vs on both sides to get Vf–Vs=at
then divide acceleration on both sides to get t=(Vf–Vs)/a
for the second problem equation need the equation a=(Vf–Vs)/t (just divide time on both sides instead of acceleration)
so you the plug in
(I don't put the units in to the problem unless needed)
1. t=(Vf–Vs)/a to t=(0–30)/-4.0
t= -30/-4.0
t=7.5 seconds
2. a=(Vf–Vs)/t to a=(10–0)/6.0
a= 10/6.0
a= 1.67m/s²
(I'm assuming the that for number two they started at rest so it would be 0m/s for velocity start)