1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nataliya [291]
3 years ago
12

Mimi bought some fabric for a sewing project. The fabric cost $15.40 per meter. She bought 250 centimeters of fabric. How much d

id Mimi pay for the fabric? Enter your answer in the box.
Mathematics
1 answer:
vazorg [7]3 years ago
5 0

Answer:

$38.5

Step-by-step explanation:

First we need to convert 250 centimeters to meters:

250 cm = 2.5 m

To find how much did Mimi pay for the fabric, we can use a rule of three:

One meter of fabric costs $15.40, so what is the cost of 2.5 m?

1 m -> 15.4

2.5 m -> x

x = 15.4 * 2.5 = $38.5

Mimi will pay $38.5 for the 250 centimeters of fabric.

You might be interested in
One third the sum of two numbers is 23.If one of the numbers is 29.3,what is the other number​
Mariana [72]
39.7 I think I’m not sure
6 0
3 years ago
Someone help asapppp
Oxana [17]

Answer:

1

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Write y=5/8x +6 in standard form using intergers
Art [367]

Answer:

5x - 8y = -48

Step-by-step explanation:

Move 5/8x to the y side to get (-5/8)x + y = 6. Multiply both sides by -8 to get 5x - 8y = -48.

8 0
2 years ago
Could someone help with the questions in the images below? I found them difficult
zubka84 [21]
Question 1a - You have got this correct, the median mark is 35
Question 1b- To work out the range, you must do the largest value subtract the smallest value. For your data, this would be 57 - 13 = 44

Question 2 - You have drawn the lines in the correct places, but you have not used a ruler. In order to get full marks on a question like this you must use a ruler.

Question 3 - Your lower quartile and median is correct, to find the upper quartile, we do 3(n/4). 'n' is the number of data points - in this case 120.
120/4 = 30
30 x 3 = 90
Go across the graph at 90 to see when the line is hit.
From what I can tell, the Upper Quartile is 3.

Next just find the maximum value.
Again, by the looks of it, the Maximum value is 8.5.

Now you have all the data needed for the box plot.

Min = 0
LQ = 0.8
Med = 2.1
UQ =  3
Max = 8.5

Using this information, draw a box plot like you did on the previous question.
<em>Again, I must stress that any line that you draw (unless purposely curved) must be drawn with a ruler; even on the graph at the top, during you working out. If you do not use a ruler, marks can be lost/taken away.</em>

Question 4a - For the median on a cumulative frequency chart, you must find the halfway point in the data. For this, we do n/2. In this case, n = 40
40/2 = 20
Draw a line (using  ruler) across at 20 until you reach the line.
Draw another one down to help you read the number.
The median looks like 34 seconds.
Question 4b - For this question, we already know the Min, Med and Max. Now we must work out the LQ and UQ.

Remember, LQ = n/4
In this case, n = 40
40/4 = 10
Look across at ten and you will find that the LQ = 16 seconds

To work out the UQ, we multiply the LQ place by 3 3(n/4).
3 x 10 = 30
30 on the graph takes us up to 45 seconds.

We now know that the:
Min = 9
LQ = 16
Med = 34
UQ = 45
Max = 57

With this information, draw a box plot like you have in the previous questions.

Question 5 - Good things to always compare on box plots are the Min/Max/Range and the Inter Quartile Range.
The boys had a lowest minimum and a higher maximum, this means that their range is larger, resulting in a large spread of data in comparison to the girls.
The Inter Quartile Range is the difference between the Upper Quartile and the Lower Quartile (how wide the box is).
The boy IQR = 45 - 16 = 29
The girls IQR = 34 - 23 = 11
Again, the girls have much more concise results; even though they did not get the quickest result, they were more like one another.

Question 5a - The median in a box plot is always the line down the centre of the box. In this case:
Median = 24 marks
Question 5b - The IQR is always the UQ - LQ
With this data, the IQR is the following:
36 - 17 = 19 marks

Hope this helps
6 0
3 years ago
Leon got a reduction of $40 on a Geometry set
SSSSS [86.1K]
I pretty sure this one is b
6 0
2 years ago
Read 2 more answers
Other questions:
  • Need help with geometric sequences <br> 30 points
    13·1 answer
  • Simplify the expression. (–h4)5
    14·2 answers
  • The seven-digit number 1113A8B can be divided by 4, 5, and 9 What is the sum of the digits A and B?
    15·1 answer
  • What is the range of this function?
    9·1 answer
  • 1-4: Find the measures of central tendency, then determine the range of the data.
    14·1 answer
  • Can someone help please
    9·2 answers
  • Isabella deposited $2,000 in an account that pays 5% simple annual interest. After one year, how much interest in dollars and ce
    5·1 answer
  • Help me with this please <br> !!!!!!!!!!!!!
    15·1 answer
  • Today eight friends went for lunch there total bill was $34.56, including tax. One of them ordered always soda and needed to pay
    6·2 answers
  • Expanded form of 3(4x+5y)
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!