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3 years ago

Does anyone know the answer? (It's not 0,4)

Mathematics

2 answers:

sweet-ann [11.9K]3 years ago

7 0

it would be any number that is within the darkest shaded area. (-4,1)

Murljashka [212]3 years ago

6 0

I believe it would be any number that is within the darkest shaded area. (-4,1) seems like it would be correct.

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30. Justify Reasoning The quotient of two negative integers results in an integer. How does the value of the quotient compare to

Ratling [72]

The quotient of 2 negative integers results in an integer.
-4/-2 = 2
the value of the quotient is positive whereas, the value of the original 2 integers are both negative. The reason being, is that when u divide two negatives, u get a positive.

6 0

3 years ago

What is the probability of rolling a 2 or not rolling a 2 using a regular 6-sided number cube?

larisa [96]

Well 100%, and 5/6 are out of the question which leaves you with 1/6 and 33.3

8 0

3 years ago

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Given that tan^2 theta=3/8,what is the value of sec theta?

algol [13]

Answer:

The value of SecФ is $\pm \sqrt{\frac{11}{8}}$ .

Step-by-step explanation:

Given as for trigonometric function :

tan²Ф = $\frac{3}{8}$

Or, tanФ = $\sqrt{\frac{3}{8} }$

∵ tanФ = $\frac{Perpendicular}{Base}$

So, $\frac{Perpendicular}{Base}$ = $\sqrt{\frac{3}{8} }$

So, Hypotenuse² = perpendicular² + base²

or, Hypotenuse² = ( $\sqrt{3}$ )² + ( $\sqrt{8}$ )²

Or, Hypotenuse² = 3 + 8 = 11

Or, Hypotenuse = ( $\sqrt{11}$ )

Now SecФ = $\frac{Hypotenuse}{Base}$

or, SecФ = $\frac{\sqrt{11}}{\sqrt{8}}$ = $\sqrt{\frac{11}{8} }$

<u>Second Method</u>

Sec²Ф - tan²Ф = 1

Or, Sec²Ф = 1 + tan²Ф

or, Sec²Ф = 1 + $\frac{3}{8}$

Or, Sec²Ф = $\frac{11}{8}$

Or, SecФ = $\pm \sqrt{\frac{11}{8}}$

Hence The value of SecФ is $\pm \sqrt{\frac{11}{8}}$ . Answer

7 0

3 years ago

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10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the

Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

$H_0: \mu = 0$

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

$H_1: \mu > 0$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

In this problem, the parameters are given as follows:

$\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50$ .

Hence, the test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}$

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by $t^{\ast} = 2.4$ .

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0

2 years ago

At Lawson Middle School, Mr. Hernandez asked 90 randomly selected students from each grade level for their favorite subject, and

kogti [31]

No he did not because 20% of 250 is 50 and there are 90 students not 50 students!! Hope this helped you a lot !!!

8 0

4 years ago

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