Answer:
The graph is shown below. The points for the graph are
and
.
Step-by-step explanation:
Given:
The function is ![f(x)=3x+1](https://tex.z-dn.net/?f=f%28x%29%3D3x%2B1)
Values of
are -2 and 2.
Evaluate the value of the function at
and
.
![f(x=-2)=3(-2)+1=-6+1=-5](https://tex.z-dn.net/?f=f%28x%3D-2%29%3D3%28-2%29%2B1%3D-6%2B1%3D-5)
![f(x=2)=3(2)+1=6+1=7](https://tex.z-dn.net/?f=f%28x%3D2%29%3D3%282%29%2B1%3D6%2B1%3D7)
Therefore, the points on the graph are
and
.
Now, we plot the points on a graph and join the line passing through the two points.
Can you research a bit? but seriously, I applied out of state, I believe it was around 30k per year
Answer:
The equation is:
f(x) = Ix + 3I - 2
Step-by-step explanation:
For a function like:
f(x) = Ix - kI + c
k is the x-value where the vertex is, and c is the y-value where the vertex is.
In the graph we can see that the vertex is in the point (-3, -2)
then:
x-value = -3 = k
y-value = -2 = c
Replacing those in the equation for the function:
f(x) = Ix - (-3)I - 2
f(x) = Ix + 3I - 2