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artcher [175]
3 years ago
9

Given the sequence 5, 6, 7, 8, ....., where x = 1, 2, 3, 4, ...., what is the first term in the sequence?

Mathematics
1 answer:
wel3 years ago
8 0

The first term in the sequence is 5.

<u>Step-by-step explanation</u>:

The sequence is 5,6,7,8,.....

  • The first term = 5
  • The second term = 6
  • The third term = 7

where x= 1,2,3,4,...

The sequence follows the pattern (x+4).

  • For x=1, then (1+4) = 5 which is the first term of the sequence.

Similarly,

  • For x=2, then (2+4) = 6 which is the second term of the sequence and the sequence follows the same pattern.
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MATH GRADE 8 15. a) and b)
Elden [556K]

Answer:   1300 cm³

a) Find the volume of the entire rectangle and subtract the volume of the missing section. Volume = L · w · h

Solid = Rectangle - Missing section  

        =  L · w · h    -   L · w · h  

        = 16 · 10 · 10 - 10 · 6 · 5

        =     1600     -     300

        =             1300

b) Find the volume of each section of the rectangle (base, left wing right wing) and add them. Volume = L · w · h

Solid =   Base       +   Left wing  +    Right wing  

        =  L · w · h    +     L · w · h   +     L · w · h

        = 16 · 10 · 5   +   5 · 10 · 5   +   5 · 10 · 5

        =     800       +     250        +      250

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The answer from (a) is the same as (b) \checkmark




6 0
4 years ago
During a rock concert, the noise level (in decibels) in front row seats has a mean of 95 dB with a standard deviation of 8 dB. W
lorasvet [3.4K]

Answer:

\frac{8}{9} *100= 88.89 \%

So we have at least 88.89% of the noise level values within 3 deviation from the mean.

Step-by-step explanation:

For this case let define the random variable X as the noise level, we know the following properties for X:

E(X) = 95 , Sd(X)= 8

And for this case we don't know the distribution for the random variable X.

But we can use the Chebysev theorem who states that the minimum percentage of the data that lies within k standard deviations from the mean is given by:

1 -\frac{1}{k^2}, k>1

So for this case we have that k = 3 and if we use this theorem we have:

1- \frac{1}{3^2}

1- \frac{1}{9}=\frac{8}{9}

And we can convert this into % and we got:

\frac{8}{9} *100= 88.89 \%

So we have at least 88.89% of the noise level values within 3 deviation from the mean.

5 0
4 years ago
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