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SOVA2 [1]
3 years ago
12

Which expression gives the volume of a sphere with radius 15?

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:

C) Volume of sphere =  \frac{4}{3} pi( 15)^{3}.

Step-by-step explanation:

Given  : sphere with radius 15.

To find : Which expression gives the volume.

Solution : We have given that radius of sphere = 15 units.

Volume of sphere =  \frac{4}{3} pi( radius)^{3}.

Plugging the value of radius

Volume of sphere =  \frac{4}{3}pi( 15)^{3}.

Therefore, C) Volume of sphere =  \frac{4}{3}π( 15)^{3}.

Nesterboy [21]3 years ago
4 0
The Volume of a Sphere = \frac{4}{3} \pi r^{3}

Thus, if the radius = 15

Then Volume of such a Sphere = \frac{4}{3} \pi (15^{3})    {OPTION C}
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Our hearts beat approximately 70 times per minute. Express in scientific notation how many times the heart beats over a lifetime
earnstyle [38]

Answer:

2.69 x 10^{9}

Step-by-step explanation:

We are given the heart's speed - 70 bpm

We count the number of minutes in 73 years :

  • 1 year = 365 days
  • 1 day = 24 hours
  • 1 hour = 60 minutes
  • 73 x 365 x 24 x 60 = 38,368,800 minutes

We multiply the heart's bpm with 73 years worth of minutes

38,368,800 x 70 = 2,685,816,000

Write the number in scientific notation = 2.68581 x 10^{9} ≈ 2.69 x 10^{9}

7 0
3 years ago
John is twice as old as Fred. Four years ago John was 6 times as old. How old is John?
kari74 [83]

I think john is 10 years old hope that helps.

7 0
3 years ago
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$725 before sales tax of 6% was added. How much was the sales tax?
likoan [24]

Answer: $768.50

Step-by-step explanation:

If $725 was the price before sales tax, $768.50 would be the total amount after the 6% sales tax increase.

***If you found my answer helpful, please give me the brainliest. :) ***

4 0
2 years ago
An element a basic substance that can’t be
Reil [10]

Answer:

Simplified

Step-by-step explanation:

Examples can be hydrogen, oxygen, gold

4 0
3 years ago
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
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