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3 years ago

What is 6/8 divided by 2/6

Mathematics

2 answers:

Alekssandra [29.7K]3 years ago

8 0

(6/8) / (2/6)
(6/8) * (6/2)
(6*6) / (8*2)
36 / 16
9 / 4
2.25

GalinKa [24]3 years ago

4 0

<span>6/8 ÷ 2/6 = 2 1/4

</span><span> How did we solve the problem above? When we divide two fractions, such as 6/8 ÷ 2/6, we flip the second fraction and then we simply multiply the numerators with each other and the denominator with each other.

We also simplify the answers to fraction problems whenever possible.</span>

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The two numbers are 39 and 22

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2 years ago

Simplify the given expression. (p+6)(p-4)

vampirchik [111]

Answer:p2+2p−24

Step-by-step explanation:(p+6)(p−4)

=(p+6)(p+−4)

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4 years ago

Read 2 more answers

What is the equation of the line represented by the table below? Х-2,-1,0,1,2 y16,11,6,1,-4

pashok25 [27]

Answer:

y = -5x + 6

Step-by-step explanation:

General equation of a line : y = mx + c......where c is intercept

To find m pick any two points..

(-2, 16) and (-1, 11)

Using (y - y¹) / (x - x¹)

(11 - 16) / (-1 - [-2]) = -5 / 1

= -5

To find c sub with any point for (x, y) and m

using (2, -4)

y = mx + c

-4 = -5(2) + c

-4 = -10 + c

6 = c

Input the values of m and c in the general equation without x and y

; y = -5x + 6

5 0

3 years ago

An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand

Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

b) We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

Part b

We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

4 0

3 years ago