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melamori03 [73]
4 years ago
10

How to do number strings

Mathematics
1 answer:
zloy xaker [14]4 years ago
6 0
I dont understand but here is a example how it may look like.

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12.<br><br>Find the Midpoint of (0,6) and (-4,8)<br><br>if you could show your work that'd be great​
Rashid [163]
The midpoint is (-2,7)!
8 0
3 years ago
Apyrotechnician plans for two fireworks to explode together at the same
olga55 [171]
First note down the relevant variables from the question.
Ua (Initial velocity a) = 320ft/s
Ub (initial velocity b) = 240ft/s
Aay (acceleration of a in the vertical axis) = Aby = -32.17ft/s/s

We want to know when they will be at the same height so should use the formula for displacement:
s = ut + 1/2 * at^2

We want to find when both firework a and firework b will be at the same height. Therefore mathematically when: say = sby (the vertical displacements of firework A and B are equal). We also know that firework B was launched 0.25s before firework A so we should either add 0.25s to the time variable for the displacement formula for firework B or subtract 0.25s for firework A.

SO:
Say = Sby
320t + 1/2*-32.17t^2 = 240(t+0.25) + 1/2 * -32.17(t+0.25)^2
320t - 16.085t^2 = 240t + 60 - 16.085(t+0.25)^2
320t - 16.085t^2 = 240t + 60 - 16.085(t^2 + 0.5t + 6.25)
320t - 16.085t^2 = 240t + 60 -16.085t^2 - 8.0425t - 100.53
320t - 240t - 8.0425t - 16.085t^2 + 16.085t^2 = 60 - 100.53
71.958t = -40.53
t = -0.56s (negative because we set t before Firework A was launched)

Now we know both fireworks explode 0.56 seconds AFTER fireworks B launches (because we added 0.25 seconds to the t variable in the equation above for the vertical displacement of Firework B).

You could continue on to find the displacement they both explode at and verify the answer by ensuring that it is equal (because the question stated they should explode at the same height by substituting the value we found for t of 0.56s into the vertical displacement formula for firework A and t+0.25s=0.81s into the same formula for Firework B

Verification:
Say = ut + 1/2at^2
Say = 320*0.56 + 1/2*-32.17*0.56^2
Say = 179.2 + -5.04
Say = 174.16ft

Sby = ut + 1/2at^2
Sby = 240*0.81 + 1/2*-32.17*0.81^2
Sby = 194.4 - 10.5
Sby = 183.9ft

While Say is close to Sby I would have expected them to be almost perfectly equal… can you please check if this matches the answer in your textbook? There could be wires due to rounding. I also usually work in SI units which use the metric system and not the imperial system although that shouldn’t make a difference. The working out and thought process is correct though and this is why trying to verify the answer is an important step to make sure it works out.

Answer: 0.56s (I think)
3 0
2 years ago
PLEASE MAKE SURE YOU ANSWER WITH THE CORRECT ANSWER!!!!!!!!
kap26 [50]
I’m not positive but I think it is square.
6 0
3 years ago
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Urgent fastttttttttttttttttttttttttttt 50 points
STatiana [176]

Answer:

I did this. But there's only 5 points . But it's ok

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2 years ago
Tony had $425.80 in his checking account. After making his car payment of $630, how much is left in his account?
zhannawk [14.2K]
If no one wants to answer your questions and what you can do is go to website that has called calculator soup and it really helps you it shows you step by step hope this helps lol
3 0
3 years ago
Read 2 more answers
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