Ask question

Ask question

All categories

Lady bird [3.3K]

3 years ago

9

Mark as brainly answerereeere asap

2 answers:

fredd [130]3 years ago

8 0

The answer is 84^2 something that helps is if you cut it up into sections

aliya0001 [1]3 years ago

5 0

Answer : 84m^2=A
Photo Shows Solving Steps.

Hope this helps!

~ Penny

You might be interested in

Find the measure of exterior angle A.

max2010maxim [7]

Answer:

40* degress angled

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Ming drew the model below to represent the equation 24+12=_x(8+4) What is the missing value in Ming's equation?

SashulF [63]

Given:

The equation is:

$24+12=\_\_\times (8+4)$

To find:

The missing value.

Solution:

We have,

$24+12=\_\_\times (8+4)$ ...(i)

Taking left hand side, we get

$24+12=3\times 8+3\times 4$

Taking 3 common, we get

$24+12=3\times (8+4)$ ...(ii)

On comparing (i) and (ii), we get

Missing value = 3

Therefore, the missing value in the given equation is 3.

4 0

2 years ago

Help me find the slope for these lines please

Eva8 [605]

Answer:

no

Step-by-step explanation:

8 0

2 years ago

Help ASAP: What is the equation by looking at this graph?

PIT_PIT [208]

If asking for y=mx+b format, the solution would be y=1x+2

8 0

3 years ago

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. Sketch the re

alukav5142 [94]

Answer:

Step-by-step explanation:

$\text{Given that:}$

$y = 1+ sec(x) \ \ y =3$

$\text{we draw the graph and the curves intersect at:}$

$x = - \dfrac{\pi}{3} \ and \ x = \dfrac{\pi}{3}$

$\text{Applying washer method;}$

$f(x) _{outer} - g(x) _{inner} --- (1)$

$V= \int ^b_a A(x) \ dx --- (2)$

$\text{outer radius = 3 - 1 = 2}$

$\text{inner radius =}$ $( 1 + sec(x) ) - 1 = sec (x)$

$A(x) = \pi ((2)^2 -(sec(x)^2) \\ \\ A(x) = \pi (4 - sec^2 (x)) ---- (3)$

$\text{The volume V =}\int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ A(x) \ dx$

$V = \int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ \pi (4- sec^2 (x) ) \ dx$

$V = 2 \pi \int ^{\dfrac{\pi}{3}}_{0}( 4 - sec^2 (x)) \ dx$

$V = 2 \pi \int ^{\pi/3}_{0} 4 . \ dx - 2 \pi \int ^{\pi/3}_{0} sec^2 (x) \ dx$

$V = 2 \pi(4) \int ^{\pi/3}_{0} 1 . \ dx - 2 \pi \Big( tan (x)\Big )^{\dfrac{\pi}{3}}_{0}$

$V = 8 \pi(x)^{\dfrac{\pi}{3}}_{0} - 2 \pi \Big( tan \dfrac{\pi}{3} -tan (0)\Big )$

$V = 8 \pi({\dfrac{\pi}{3}}-{0}) - 2 \pi \Big( tan \sqrt{3}-(0)\Big )$

$V = 8 \pi({\dfrac{\pi}{3}}) - 2 \pi \Big( \sqrt{3}\Big )$

$\mathbf{V = 2 \pi \Big(\dfrac{4\pi}{3}- \sqrt{3} \Big)}$

8 0

2 years ago