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3 years ago

Can somebody explain how to do this problem?

Mathematics

2 answers:

V125BC [204]3 years ago

6 0

Physicsforums.com has step by step explanation but here is example
y=-9e-19x^6+2e-14x^5-2e-10x^4+1e-06x^3-0.0027x^2+3.5222x-1656.5
shorthand =(10^-9)-(19x*x^6)etc..... go to physics sight it breaks different examples down. sorry i couldnt give u direct answer but i always have to find example problems to walk me thru it as needed

saul85 [17]3 years ago

6 0

Let e^-3x be u,
10u^-2=5u
10/u^2=5u
5u^3=10
u^3=10/5
u=1.25992105
e^-3x=1.25992105
-3x=0.2310490602
x=-0.0770
Method 2
10e^6x=5e^-3x
10e^6x-5e^-3x=0
5e^-3x(2e^9x-1)=0
2e^9x-1=0
2e^9x=1
e^9x=1/2
9x=loge1/2
x=(loge1/2)/9
=-0.0770

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What is 5.316 - 1.942 btw (show ur work) :)

erastovalidia [21]

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$\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}$

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$\frac{\begin{matrix}\:\:&5&.&3&1&\textbf{6}\\ -&1&.&9&4&\textbf{2}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\:\:&\textbf{4}\end{matrix}}$

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$\frac{\begin{matrix}\:\:&4&\:\:&\textbf{13}&\:\:&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{3}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}$

$\frac{\begin{matrix}\:\:&4&\:\:&\textbf{12}&10&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{13}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}$

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$\frac{\begin{matrix}\:\:&4&\textbf{\:\:}&12&11&\:\:\\ \:\:&\linethrough{5}&\textbf{.}&\linethrough{13}&\linethrough{1}&6\\ -&1&\textbf{.}&9&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\textbf{.}&3&7&4\end{matrix}}$

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