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Firdavs [7]
3 years ago
8

What are the real or imaginary solutions of the polynomial equation x*4-25=0​

Mathematics
1 answer:
Paul [167]3 years ago
5 0

Hello from MrBillDoesMath!

Answer:

Solutions: x = +\- 5i or x = +\- sqrt(5)


Discussion:

Factor x^4 - 25:

x^4 - 25     = (x^2+5) (x^2-5)                              =>  factor x^2 - 5

x^4 - 25 =   (x^2+5)(x + sqrt(5)) (x - sqrt(5))       => factor x^2 + 5

x^4 = 25  = (x +5i)(x-5i) (x + sqrt(5)) (x - sqrt(5))  

Hence the solutions are

x = +\- 5i and x = +\- sqrt(5)



Thank you,


MrB

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Answer:

¿en qué periodos  le tocará participar?

El equipo cuatro participa en el periodo 5 - 11 - 17

¿Todos los equipos participarán el mismo  número de veces?

Todos los equipos los hacen 3 veces . menos 1 equipo que lo hace 2 veces

¿Por qué?

Cuatrimestre. =  120 dias

Numero de semanas = 120/ 7  17,1

17 semanas completas 3 dias

No se trabaja la primera semana. por lo que quedan 16 semana 3 dias.

Son 6 equipos para participar todos serian por lo menos 17 semanas 1 dia.

Step-by-step explanation:

Cuatrimestre. =  120 dias

Numero de semanas = 120/ 7  17,1

17 semanas completas 3 dias

No se trabaja la primera semana. por lo que quedan 16 semana 3 dias.

Son seis equipos.   17 ( 16,3) semanas / 6

Todos los equipos los hacen 3 veces . menos 1 equipo que lo hace 2 veces

Semana 1 2 3 4 5 6

Equipos

1        

2  X      

3   X    

4    X    

5     X  

6      X  

7       X

8  X      

9   X    

10    X    

11     X  

12      X  

13       X

14  X      

15   X    

16    X    

17     X  

18      X  

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2 years ago
An admiral, captain, and commander, all different, are to be chosen from a group of 10 Starfleet officers. How many different ch
zepelin [54]

Answer:

10C1 *9C1*8C1 = 10*9*8=720

Step-by-step explanation:

For this case in order to select the one admiral, captain and commander, all different. We are assuming that the order in the selection no matter, so we can begin selecting an admiral then a captain and then a commander.

So we have 10C1 ways to select one admiral since we want just one

Now we have remaining 9 people and we have 9C1 ways to select a captain since we want a captain different from the admiral selected first

Now we have remaining 8 people and we have 8C1 ways to select a commander since we want a commander different from the captain selected secondly.

The term nCx (combinatory) is defined as:

nCx = \frac{n!}{x! (n-x)!}

And by properties nC1= n

So then the number of possible way are:

10C1 *9C1*8C1 = 10*9*8=720

If we select first the captain then the commander and finally the admiral we have tha same way of select 10*9*8=720

For all the possible selection orders always we will see that we have 720 to select.

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