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Firdavs [7]
3 years ago
8

What are the real or imaginary solutions of the polynomial equation x*4-25=0​

Mathematics
1 answer:
Paul [167]3 years ago
5 0

Hello from MrBillDoesMath!

Answer:

Solutions: x = +\- 5i or x = +\- sqrt(5)


Discussion:

Factor x^4 - 25:

x^4 - 25     = (x^2+5) (x^2-5)                              =>  factor x^2 - 5

x^4 - 25 =   (x^2+5)(x + sqrt(5)) (x - sqrt(5))       => factor x^2 + 5

x^4 = 25  = (x +5i)(x-5i) (x + sqrt(5)) (x - sqrt(5))  

Hence the solutions are

x = +\- 5i and x = +\- sqrt(5)



Thank you,


MrB

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The slope of a line is -1/3, and the y-intercept is 10/3. What is the equation of the line written in general form?
Y_Kistochka [10]
The answer is:  [B]:  " x  + 3y + 10 = 0 " .
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Explanation:
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Note the equation for a line; in 'slope-intercept form':  "y = mx + b" ;
 
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So, given the information in this very question/problem:
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slope = m = (-1/3) ; 
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And we can write the equation of the line; in "slope-intercept form"; that is:
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   " y = (-1/3)x + (10/3) " ;
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Now, the problem asks for the equation of this line; in "general form";  or "standard format";  which is:
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   "Ax + By + C = 0 " ; 
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So; given: 
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